All categories

3 years ago

What does the monomer unit of Polyester look like? And what’s its chemical formula?

Chemistry

1 answer:

AlladinOne [14]3 years ago

6 0

Answer:

The monomers of polyesters are,

(i) A Dicarboxylic Acid

(ii) A Dialcohol

Explanation:

As depicted from name polyester is a macromolecule which contains numerous ester functional groups. Ester is formed by the condensation of Carboxylic acid and alcohol as shown,

R-COOH + R'OH → RCOOR' + H₂O

Therefore, in order to utilize this reaction for the formation of long chain of polyesters then one can use a dicarboxylic compounds and dialcohol compounds. This will allow to propagate the chain length depending upon the requirement. Hence, the general reaction for the formation of polyester is shown below. The circle and rectangle specifies different moieties which imparts different characters to the polyester.

You might be interested in

A jug contains 2L of milk. Calculate the volume of the milk in m3

stepan [7]

Answer: 0.002 m³

Explanation:

We can use our unit conversions to find the volume in m³.

$2L*\frac{1m^3}{1000L} =0.002m^3$

8 0

3 years ago

Hurry please!

Pani-rosa [81]

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at $20^oC$ is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in $\frac{27g}{9.02g}\times 100ml=299.33ml$ of water

The volume of water is 299.33 ml.

As we know that the density of water at $20^oC$ is 0.9982 g/ml

Now we have to calculate the mass of water.

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}$

$\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g$

Therefore, the mass of of water present in the jar is, 298.79 g

5 0

3 years ago

How many liters of CO2 gas can be produced at 30.0 °C and 1.50 atm from the reaction of 5.00 mol of C3H8 and an excess of O2 acc

lbvjy [14]

Answer:

249 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 5.00 moles of C₃H₈

The molar ratio of C₃H₈ to CO₂ is 1:3. The moles of CO₂ produced are 3/1 × 5.00 mol = 15.0 mol

Step 3: Convert "30.0°C" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 30.0°C + 273.15 = 303.2 K

Step 4: Calculate the volume of carbon dioxide

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 15.0 mol × 0.0821 atm.L/mol.K × 303.2 K/1.50 atm

V = 249 L

5 0

3 years ago

How many molecules of hypothetical substance b are produced when 29.9g of hypothetical substance a reacts? the molar mass of sub

Andrej [43]

<span>1.15x10^24 molecules of hypothetical substance b Making the assumption that each molecule in hypothetical substance a reacts to produce a single molecule of hypothetical substance b, then the number of molecules of substance b will be the number of moles of substance a multiplied by avogadro's number. So Moles hypothetical substance a = 29.9 g / 15.7 g/mol = 1.904458599 moles This means that we should also have 1.904458599 moles of hypothetical substance b. And to get the number of atoms, multiply by 6.0221409x10^23, so: 1.904458599 * 6.0221409x10^23 = 1.146892x10^24 molecules. Rounding to 3 significant figures gives 1.15x10^24</span>

5 0

3 years ago

5. A standardized mass was known to weigh exactly 5.0000g. It was weighed on a newly

sergey [27]

Answer:

Absolute error $= 0.001$