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2 years ago

#12 PLEASE HELP IM TAKING A TIMED TEST

Chemistry

1 answer:

Goshia [24]2 years ago

3 0

Answer:

Option B

Explanation:

For the problem in question 12, option B is the correct choice. It rightly expresses how electrons will fill the third energy level of aluminum.

Aluminum is an element with 13 electrons. It has 3 energy levels.

The shell notation is given as 2 8 3

Sublevel notation = 1s² 2s² 2p⁶ 3s² 3p¹

The third energy level is given as 3s² 3p¹

We can represent it as: ⇅ ↑

3s² 3p¹

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hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

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