All categories

3 years ago

Which of the following is a helpful process in evaluating scientific claims?

2 answers:

8 0

Answer: D. If you look at the claims with critical thinking then you will be less likely to be fooled by something false

Agata [3.3K]3 years ago

7 0

Answer: d. critical thinking

Explanation:

A scientific claim is a statement which is based on evidences obtained after the experimental trials and direct observatory approach of the process occurring in the nature.

Critical thinking based on the approach of verification and analysis can be used to evaluate the scientific claims. The result of evaluation will be reliable and acceptable. The evaluation should not be biased or presumed it will yield inappropriate results.

You might be interested in

Suppose a ball is dropped from shoulder height, falls, makes a perfectly elastic collision with the floor, and rebounds to shoul

Bezzdna [24]

Answer:Same magnitude

Explanation:

When ball is dropped from shoulder height h then velocity at the bottom is given by

$v_1=\sqrt{2gh}$

if it makes elastic collision then it will acquire the same velocity and riser up to the same height

If m is the mass of ball then impulse imparted is given by

$J=m(v_2-v_1)$

$J=2m\sqrt{2gh}$

Thus impulse imparted by gravity and Floor will have same magnitude of impulse but direction will be opposite to each other.

7 0

3 years ago

A rubber ducky is placed 20 cm from a thin convex lens with a focal length of 15 cm. Which statement correctly describes the nat

blondinia [14]

I believe the answer is B, a real and inverted image is formed on the side of the lens opposite the rubber ducky. The focal length is 15 cm and therefore the center of curvature (2F) will be 30 cm. When the object is placed between F and 2F (in this case 20 cm) in front of a convex lens, an inverted, real image is formed on the other side of the lens.

6 0

3 years ago

Read 2 more answers

A diagram of a closed circuit with a power source on the left labeled 6 V. There are 3 resistors in parallel, separate paths, co

AfilCa [17]

Answer:

Current: 1.0 Amperes

The minimum current is flowing through path D

Explanation:

We first find the equivalent resistance to the three resistors in parallel ( which is the total resistance of the circuit) via the equation:

$\frac{1}{R_e} =\frac{1}{R_B}+\frac{1}{R_C}+\frac{1}{R_D}\\\frac{1}{R_e} =\frac{1}{10}+\frac{1}{20}+\frac{1}{50}=0.17\\R_e=(1/0.17)\Omega\\R_e=5.88 \Omega$

with this info, we can estimate the current going through branch A using Ohm's Law, and the information that the power source is 6 V:

$V=I*R\\6V=I*5.88\Omega\\I=\frac{6}{5.88} Amp\\I=1.02A$

where the current comes in units of Amperes since all other the quantities are given in the SI system, and we can round this answer to 1.0 Amp following the request to round it to the tenth.

The current will be the lowest through the branch with the largest resistor due to the fact that less current will flow through the path of more resistance.

Than means that the lowest current will be registered through branch D where the 50 $\Omega$ resistor is.

8 0

3 years ago

Read 2 more answers

A 10.0kg water balloon is dropped from a height of 12.0m. Calculate the speed of the balloon just before it hits the ground

kolbaska11 [484]

Answer:

15.5 m/s.

Explanation:

Potential energy of the balloon has been converted to kinetic energy.

potential energy = kinetic energy.

mgh = ½mv².

10* 10* 12= ½ *10 *v²

1200 = 5v²

v²=1200÷5

v=√240

v= 15.49~15.5 m/s.

5 0

2 years ago

Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t

alexandr1967 [171]

Answer:

a) the one with a lower orbit b) the one with a higher orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

$\frac{v^2}{r} = \frac{GM}{r^2}$ .

so the velocity is

$v = \sqrt{\frac{GM}{r} }$

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

$T = 2\pi \sqrt{\frac{a^3}{GM} }$

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0

3 years ago