Hi there!
Using Hooke's Law:
F = Force (N)
k = Spring constant (N/m)
x = displacement from equilibrium
We are given the force and displacement, so solve for 'k':
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Answer: hello some of your values are wrongly written hence I will resolve your question using the right values
answer:
stiffness = 1.09 * 10^-6 N/m
Explanation:
Given data:
Length ( l ) = 16 m
radius of wire ( r ) = 3.5 m
mass ( m ) = 5kg
<u>Distance stretched ( Δl ) = 4 * 10^-3 m </u> ( right value )
<u>average bond length ( between atoms ) = 2.3 * 10^-10 m </u>( right value)
first step : calculate the area
area ( A ) = πr^2 = π * ( 3.5)^2 = 38.48 m^2
γ = MgL / A Δl
= [ (5 * 9.81 * 16 ) / ( 38.48 * (4.3*10^-3) ) ]
= 784.8 / 0.165 = 4756.36 N/m^2
hence : stiffness = γ * bond length
= 4756.36 * 2.3 * 10^-10 = 1.09 * 10^-6 N/m
It determines whether the light beams will be concentrated or scattered.
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