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3 years ago

A 10.0kg water balloon is dropped from a height of 12.0m. Calculate the speed of the balloon just before it hits the ground

Physics

1 answer:

kolbaska11 [484]3 years ago

5 0

Answer:

15.5 m/s.

Explanation:

Potential energy of the balloon has been converted to kinetic energy.

potential energy = kinetic energy.

mgh = ½mv².

10* 10* 12= ½ *10 *v²

1200 = 5v²

v²=1200÷5

v=√240

v= 15.49~15.5 m/s.

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In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue

Tomtit [17]

a) p₀ = 1.2 kg m / s

b) p_f = 1.2 kg m / s

c) $v_{2f}$ = 1.278 m/s

d)1.2482 = $v_{2f}$ cos θ

e) 0.2736 = $v_{2f}$ sin θ

g) θ = 12.36

<h3>What is momentum?</h3>

Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.

According to the question,

We define a system formed by the two balls, which are isolated and the forces during the collision are internal.

Hence , the momentum is conserved

a) The momentum of the system before the collision:

$p_o = m v_1_0 + 0 p_o= 0.6 2 p_o = 1.2 kg m / s$

b) The momentum of the system after the collision, as the system is isolated, the momentum is conserved so

$p_f = 1.2 kg m / s$

d. On X axis

$p_ox$ = 1.2 kg m / s

$p_{fx}$ = m v1f cos 20 + m v2f cos θ

$p_o = p_f$

1.2 = 0.6 (-0.8) cos 20+ 0.6 $v_{2f}$ cos θ

1.2482 = $v_{2f}$ cos θ

e. On Y axis

$p_{oy} = 0$

$p_{fy}$ = m $v_{1f}$ sin 20 + m $v_{2f}$ cos θ

0 = 0.6 (-0.8) sin 20 + 0.6 $v_{2f}$ sin θ

0.2736 = $v_{2f}$ sin θ

Here,

g. we write our system of equations

0.2736 = $v_{2f}$ sin θ

1.2482 = $v_{2f}$ cos θ

0.219 = tan θ (divide)

θ = tan⁻¹ 0.21919

θ = 12.36

c. Now To find the velocity

0.2736 = $v_{2f}$ sin θ

$v_{2f}$ = 0.2736 / sin 12.36

$v_{2f}$ = 1.278 m / s

Learn more about momentum here:

brainly.com/question/4956182

#SPJ1

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2 years ago

a group of students working in a high school chemistry lab believe they have discovered a new element! how exciting! upon furthe

maw [93]

Explanation:

From the experiment:

Number of protons = 74

Number of neutrons = 110

Number of protons in an element is the atomic number of the element. It is used to locate and position and element on the periodic table.

For a neutral or uncharged atom, the number of protons is the same as the number of electrons.

The element whose number of protons or atomic number if 74 is Tungsten

Mass number = 74 + 110 = 184g/mol

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3 years ago

The box shown on the rough ramp above is sliding up the ramp.calculate the force of friction on the box

Anna [14]

We are given a box that slides up a ramp. To determine the force of friction we will use the following relationship:

$F_f=\mu N$

Where.

$\begin{gathered} N=\text{ normal force} \\ \mu=\text{ coefficient of friction} \end{gathered}$

To determine the Normal force we will add the forces in the direction perpendicular to the ramp, we will call this direction the y-direction as shown in the following diagram:

In the diagram we have:

$\begin{gathered} m=\text{ mass}_{} \\ g=\text{ acceleration of gravity} \\ mg=\text{ weight} \\ mg_y=y-\text{component of the weight. } \end{gathered}$

Adding the forces in the y-direction we get:

$\Sigma F_y=N-mg_y$

Since there is no movement in the y-direction the sum of forces must be equal to zero:

$N-mg_y=0$

Now we solve for the normal force:

$N=mg_y$

To determine the y-component of the weight we will use the trigonometric function cosine:

$\cos 40=\frac{mg_y}{mg}$

Now we multiply both sides by "mg":

$mg\cos 40=mg_y$

Now we substitute this value in the expression for the normal force:

$N=mg\cos 40$

Now we substitute this in the expression for the friction force:

$F_f=\mu mg\cos 40$

Now we substitute the given values:

$F_f=(0.2)(10\operatorname{kg})(9.8\frac{m}{s^2})\cos 40$

Solving the operations:

$F_f=15.01N$

Therefore, the force of friction is 15.01 Newtons.

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1 year ago

All of the following processes are the ones that lead directly to the formation of sedimentary rock EXCEPT-

emmasim [6.3K]

Answer:

melting of rock deep underground.

Explanation:

The melting of rocks deep underground does not produce sedimentary rocks. Most igneous rocks are produced by this process.

When molten rocks underground called magma is solidified in the subsurface, it results into the formation of igneous bodies.

Sedimentary rocks forms by the accumulation of sediments.
Inside the basin where the sediments are deposited, they are compacted, cemented and lithified.
Chemical and physical weathering of rocks produces sediments.

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2 years ago

If I were a geologist working in South America along one of those plate boundaries, what might I see if I were looking at sedime

faust18 [17]

Answer:

you'll see rocks that have been there for years

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3 years ago