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3 years ago

In a nucleotide, we find which other biomolecule(s) making up a piece of the nucleotide itself?

1 answer:

7 0

In a nucleotide, we find CARBOHYDRATE making up a piece of the nucleotide itself. An example of the type of carbohydrate found in nucloetides is de-oxy ribose. Deoxyribose is a five carbon sugar {pentose} which is part of the building blocks of nucleotide.<span />

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Highest ionization energy: Li, Be, B

Ad libitum [116K]

Hello!

On the periodic table, as we go down the periodic table, the ionization energy decreases, but as we go across the periodic table (left to right), the ionization increases.

On the periodic table, lithium (Li) is located in column one, beryllium (Be) is located in column two, and (B) boron is located in column 13. As stated above, when we go across the periodic table (left to right), the ionization increases.

Therefore, the element with the highest ionization energy is Boron, or symbol B on the period table.

3 0

3 years ago

Round off the following to three significant figures 0.032000000cg

tino4ka555 [31]

<span>0.032000000 cg

Rounding off ........>

0.0320 cg

The last zero means the measurement is accurate to that digit
</span>

6 0

3 years ago

Graphite and diamond are both solid forms of the element carbon. Which statement explains

vlada-n [284]

Answer: C diamond has a different crystal structure from graphite

Explanation:

3 0

2 years ago

A solution of h2so4(aq) with a molal concentration of 2.24 m has a density of 1.135 g/ml. what is the molar concentration of thi

OLga [1]

This problem is simply converting the concentration from molality to molarity. Molality has units of mol solute/kg solvent, while molarity has units of mol solute/L solution.

2.24 mol H2SO4/kg H2O * (0.25806 kg H2SO4/mol H2SO4) = 0.578 kg H2SO4/kg H2O

That means the solution weighs a total of 1 kg + 0.578 kg = 1.578 kg. Then, convert it to liters using the density data:

1.578 kg * (1000g / 1kg) * (1 mL/1.135 g) = 1390 mL or 1.39 L.

Hence, the molarity is

2.24/1.39 = 1.61 M

7 0

3 years ago

The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.

Nonamiya [84]

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

8 0

3 years ago