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4 years ago

In a nucleotide, we find which other biomolecule(s) making up a piece of the nucleotide itself?

1 answer:

7 0

In a nucleotide, we find CARBOHYDRATE making up a piece of the nucleotide itself. An example of the type of carbohydrate found in nucloetides is de-oxy ribose. Deoxyribose is a five carbon sugar {pentose} which is part of the building blocks of nucleotide.<span />

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True or false

Ivanshal [37]

Answer:

true because of the elements

4 0

3 years ago

Calculate the volume of 11 g of CO2 at NTP ?

Kitty [74]

<h3>Answer:</h3>

5.6 Liters

<h3>Explanation:</h3>

N.T.P. refers to the standard temperature and pressure (S.T.P).

We need to know that;

One mole of a gas occupies a volume of 22.4 liters at N.T.P.

In this case;

We have 11 g of CO₂

But, 1 mole of CO₂ occupies 22.4 l at N.T.P.

1 mole of CO₂ = 44 g

Therefore;

44 g of CO₂ = 22.4 liters

What about 11 g ?

= (11 g × 22.4 l)÷ 44 g

= 5.6 l

Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.

8 0

4 years ago

Iodine 131, cesium 137, and strontium 90 are all considered isotopes. What are isotopes?

Nitella [24]

Answer:

Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.

Explanation:

If the number of protons had changed then it would just be a different element.

Electron number changing simply adds charge to the atom, and doesn't change it or anything.

PLS GIVE BRAINLIEST

3 0

3 years ago

Read 2 more answers

Help mark brainliest !! Both dehydration and water addition to alkenes use h2so4 as a catalyst.Which is the difference between t

sasho [114]

Can u take a picture of it

7 0

3 years ago

To measure the speed of a car, we use miles per hour (miles/hour or mi/h or mph). To measure the rate of a reaction we use molar

arsen [322]

Answer:

Part A: 47.8 mi/h

Part B: 0.072 M/s

Part C: 0.144 M/s

Explanation:

Part A

The average speed or velocity (V) is the variation of the space divided by the variation of the time:

V = (241 - 2)/(8 -3)

V = 47.8 mi/h

Part B

As Part A, the average rate (r) of formation of I2 is the variation of the concentration divided by the variation of time:

r = (1.83 - 1.11)/(15 - 5)

r = 0.072 M/s

Part C

The rates of the substances are proportional of their number of moles (n) which are their coefficient, so:

rI2/nI2 = rHCl/nHCl

0.072/1 = rHCl/2

rHCl = 2*0.072

rHCl = 0.144 M/s

7 0

3 years ago