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professor190 [17]
3 years ago
15

Solution A has a concentration of 3 M. If solution B is 5 times more concentrated than A what is it’s concentration?

Chemistry
1 answer:
raketka [301]3 years ago
5 0

The answer is 15 M!!

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3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?
Leno4ka [110]

Answer:

Option A (9.0) is the correct alternative.

Explanation:

The given values are:

Molarity,

= 1.5 M

Volume,

= 6000 mL

or,

= 6 L

As we know,

⇒ Molarity=\frac{Moles}{Volume}

or,

⇒ The \ moles \ of \ NaCl=Molarity\times Volume

By putting the values, we get

                                     =1.5\times 6

                                     =9 \ mol

7 0
3 years ago
Explain how the presence of several oxygen atoms ina compound containing an-OH group can make the compound acidic.
Lina20 [59]
<span>In each case, the same bond gets broken - the bond between the hydrogen and oxygen in an -OH group. Writing the rest of the molecule as "X"
</span>

The factors to consider

Two of the factors which influence the ionisation of an acid are:

<span>the strength of the bond being broken,the stability of the ions being formed.</span>

In these cases, you seem to be breaking the same oxygen-hydrogen bond each time, and so you might expect the strengths to be similar.

7 0
3 years ago
The formula C2H4 can be classified as
blsea [12.9K]

The formula C2H4 can be classified as both a molecular formula and an empirical formula. The answer is number 4.

7 0
4 years ago
Read 2 more answers
A sample of paper from an ancient scroll was found to contain 39.5% 14C content as compared to a present-day sample. The t1/2 fo
nirvana33 [79]

Answer

7665 years

Procedure

Let N₀ be the amount of carbon-14 present in a living organism. According to the radioactive decay law, the number of carbon-14 atoms, N, left in a dead tissue sample after a certain time, t, is given by the exponential equation:

N = N₀e^(-λt)

where λ is the decay constant which is related to half-life (T1/2) by the equation:

\lambda=\frac{ln(2)}{t_{\frac{1}{2}}}

Here, ln(2) is the natural logarithm of 2.

The percent of carbon-14 remaining after time t is given by N/N₀.

Using the first equation, we can determine λt.

The half-life of carbon-14 is 5,720 years, thus, we can calculate λ using the second equation, and then find t.

\lambda=\frac{ln(2)}{5720}=1.211\times10^{-4}

Solving the second equation for t, and using the λ we have just calculated we will have

t= 7665 years

3 0
1 year ago
One end has a specific binding site for a particular amino acid and the other end
BARSIC [14]
One end has a specific binding site for a particular amino acid and the other end  the sequence that can pair with a codon, called an anticodon. The DNA code is translated into messenger RNA when the RNA polymerase binds to it and makes the mRNA copy.
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3 years ago
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