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dmitriy555 [2]
3 years ago
14

49.Which of the following statements regarding chemical equilibrium is true?

Chemistry
1 answer:
crimeas [40]3 years ago
8 0
A asystem at equilibrium stops
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Pls help Combustion is commonly referred to as _____.
kati45 [8]

Answer:

Combustion is a chemical reaction in which a substance reacts with air to form energy.

Explanation:

Hope that this is helpful.

Have a great day.

7 0
2 years ago
Which scientist established the law of octaves ?
goblinko [34]

the answer is D. John Newlands <3

5 0
3 years ago
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2H2 +O2 = 2H2O balance equation with 5 oxygen
Ivenika [448]

10H₂    +   5O₂ →    10H₂O

Explanation:

This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:

   "In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

This meaning of this is that; the number of atoms on each side of the expression must be the same.

                    2H₂    +   O₂ →    2H₂O

let us check is the equation above is balanced;

   

                                      2H₂    +   O₂ →    2H₂O

Elements             reactant                product

H                                  4                           4

O                                   2                           2

We can see vividly that the equation is balanced;

Now; if we have 5 oxygen gas, we multiply the equation through by 5:

 

                                 5 x          (  2H₂    +   O₂ →    2H₂O   )

     ⇒        10H₂    +   5O₂ →    10H₂O

Elements             reactant                product

H                                  20                       20

O                                  10                        10

learn more:

Balanced equation brainly.com/question/11102790

#learnwithBrainly

5 0
4 years ago
_A1Br3+_K=_KBr+_A1<br> fill in the correct coefficients.
Nataly_w [17]
1 A1Br3 + 3 K = 3 KBr + 1 A1
3 0
3 years ago
7.26 of a hydrate, Cu(NO3)2.xH2O, formed 2.4 g copper(II) oxide.
goldfiish [28.3K]

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

1) n CuO = 2.4g / 79.54g/mol = 0.03 mol CuO

2) n Cu(NO3)2.xH2O = 7.26 g / 205.6 = 0.035 moles of Cu(NO3)2.xH2O

3) 205.6 g

Cu = 63.5 g

N = 14g

O =16g

H= 1 g

63.5+ (14+(16*3))*2+1*2+16 =205.6 g

4) yes is 188g

5) I don’t know, I assume was 1

6 0
4 years ago
Read 2 more answers
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