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MrRissso [65]
3 years ago
14

g A rod is 2.0 m long and lies along the x-axis, with one end at the origin. A force of 25 N is applied at the point x = 1.2 m,

and is directed 30° above the x-axis. What is the torque on the rod?
Physics
1 answer:
Nataly [62]3 years ago
6 0

Answer:

τ = 15N.m

Explanation:

Torque on the rod is given by:

\tau=F*sin(30\°)*d

\tau=25*0.5*1.2

\tau=15N.m

If you were told that gravity contributes as well, and you were given the mass of the rod, you would have to subtract the torque of the weight to this value.

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