Question

g A rod is 2.0 m long and lies along the x-axis, with one end at the origin. A force of 25 N is applied at the point x = 1.2 m, and is directed 30° above the x-axis. What is the torque on the rod?

Answer 1

Answer:

τ = 15N.m

Explanation:

Torque on the rod is given by:

$\tau=F*sin(30\°)*d$

$\tau=25*0.5*1.2$

$\tau=15N.m$

If you were told that gravity contributes as well, and you were given the mass of the rod, you would have to subtract the torque of the weight to this value.