Answer:
the charge that is given by the object is positive charge and the object which is taking the charge is negetively charged
Explanation:
Answer:
The specific heat for the metal is 0.466 J/g°C.
Explanation:
Given,
Q = 1120 Joules
mass = 12 grams
T₁ = 100°C
T₂ = 300°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
ΔT = T₂ - T₁ = 300°C - 100°C = 200°C
Substituting values,
1120 = (12)(200)(Cp)
Cp = 0.466 J/g°C.
Therefore, specific heat of the metal is 0.466 J/g°C.
<span>Longitudinal waves travel through a series of compression's and </span>rarefaction's.<span />
Answer:
The Magnetic field is 59.13 mT.
Explanation:
Given that,
Number of turns = 400
Radius = 1.0 cm
Frequency = 90 Hz
Emf = 4.2 V
We need to calculate the angular velocity
Using formula of angular velocity
We need to calculate the magnetic flux
Relation between magnetic flux and induced emf
Put the value into the formula
Hence, The Magnetic field is 59.13 mT.
2.440
X 107. The magnitude
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244.000
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261.080