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ioda
3 years ago
12

The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H+ (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) Cal

culate the potential at 310 K for this battery when [H+ ] = [HSO4 - ] = 4.5 M. At 310 K E o = 2.08 V for the lead storage battery. (a) 2.10 V (b) 2.24 V (c) 2.16 V (d) 2.12 V (e) not enough inf
Physics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

d) 2.12 V

Explanation:

E =E° - RT/nF log 1/H⁺ x HSO₄⁻

E = 2.08 - ( .059/2 X log 1/4.5x4.5 )

2.08 - (-0.038 ) = 2.118 =2.12 V

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Answer:

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The answer is C! I knew this way before taking the test

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3. in adlerian therapy, clients learn how core beliefs that have been helpful in the past might not work well now and then to pu
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8 0
1 year ago
a ship travels a port p and travels 30 km due north. then it changes course and travels 20 km in a direction  30° east of north
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When we represent what is given to us on a coordinate plane, we have a figure as shown in the attachment.

To find the distance between P and R, we have to find the Net Displacement of the ship (brown arrow in the figure).

For that, we use the rules for Vector addition.

We see that the first displacement D_{1} = 30 km (blue arrow) is along the y-axis, but the second part of the ship's journey D_{2} = 20 km (red arrow) is at an angle with reference to y-axis.

So, we first find the components of the red arrow along X and Y.

Component of D_{2} along X-axis is given by  D_{2x}  = D_{2} Sin 30 = 10 km

Component of D_{2} along Y-axis is given by  D_{2y}  = D_{2} Cos 30 = 17.32 km

We now add all the vectors along X and along Y separately.

Net Displacement along X  D_{netX} = 10 km

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Now that we have the components of the net displacement along X and Y, we make use of Pythagorean Theorem to calculate the D_{net}

D_{net}  = \sqrt{D_{netX} ^{2} + D_{netY} ^{2}}

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3 years ago
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