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ioda
3 years ago
12

The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H+ (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) Cal

culate the potential at 310 K for this battery when [H+ ] = [HSO4 - ] = 4.5 M. At 310 K E o = 2.08 V for the lead storage battery. (a) 2.10 V (b) 2.24 V (c) 2.16 V (d) 2.12 V (e) not enough inf
Physics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

d) 2.12 V

Explanation:

E =E° - RT/nF log 1/H⁺ x HSO₄⁻

E = 2.08 - ( .059/2 X log 1/4.5x4.5 )

2.08 - (-0.038 ) = 2.118 =2.12 V

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A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

Q water + Q copper = Q surroundings =0 (insulated)

Q water = - Q copper

since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg *  0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

m w= 0.3 kg

7 0
4 years ago
State Archimedes' principle.
vampirchik [111]

Answer:

Archimedes' principle states that, when a body is partially or completely immersed in a fluid, it experiences an apparent loss in weight that is equal to the weight of the fluid displaced by the immersed part of the body.

Explanation:

Archimedes' principle allows the buoyancy of an object partially or fully immersed in a fluid to be calculated. The downward force on the object is simply its weight. Thus, the net force on the object is the difference between the magnitudes

of the buoyant force and its weight. If this net force is positive, the object rises; if negative, the object sinks; and if zero, the object is neutrally buoyant - that is, it remains in place without either rising or sinking. In simple words,

8 0
3 years ago
Read 2 more answers
Which of the following statements is an explanation? A. Aggressive chimpanzees should be monitored during meal times or fed sepa
ratelena [41]

Answer:

C?

Explanation:

My best guess would be C as it's the only answer that gives a reason behind the statement.

5 0
4 years ago
Read 2 more answers
Two carts undergo an inelastic collision where they stick together. Cart A has an initial velocity v0, and the second cart B is
dimulka [17.4K]

Answer:

Explanation:

Initial kinetic energy of the system = 1/2 mA v0²

If Vf be the final velocity of both the carts

applying conservation of momentum

final velocity

Vf = mAvo / ( mA +mB)

kinetic energy ( final ) =  1/2 (mA +mB)mA²vo² /  ( mA +mB)²

= mA²vo²  / 2( mA +mB)

Given 1/2 mA v0²  / mA²vo²  / 2( mA +mB) = 6

mA v0² x ( mA +mB) / mA²vo² = 6

( mA +mB) / mA = 6

mA + mB = 6 mA

5 mA = mB

mB / mA = 5 .

3 0
4 years ago
Find the deBroglie wavelength of an electron with 4.0 eV.
pantera1 [17]

Explanation:

It is given that,

Voltage, V=4 eV=4\times 1.6\times 10^{-19}\ V= 6.4\times 10^{-19}\ V

De broglie wavelength in terms of voltage is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

m and e are the mass and charge on electron. So,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{6.4\times 10^{-19}} }\ A  

\lambda=1.53\times 10^{10}\ A

\lambda=1.53\ m

So, the De broglie wavelength of an electron is 1.53 meters. Hence, this is the required solution.      

3 0
3 years ago
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