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ioda
3 years ago
12

The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H+ (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) Cal

culate the potential at 310 K for this battery when [H+ ] = [HSO4 - ] = 4.5 M. At 310 K E o = 2.08 V for the lead storage battery. (a) 2.10 V (b) 2.24 V (c) 2.16 V (d) 2.12 V (e) not enough inf
Physics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

d) 2.12 V

Explanation:

E =E° - RT/nF log 1/H⁺ x HSO₄⁻

E = 2.08 - ( .059/2 X log 1/4.5x4.5 )

2.08 - (-0.038 ) = 2.118 =2.12 V

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What are the conditions of the thermonuclear fusion reaction in the sun?​
Verizon [17]

High temperature gives the hydrogen atoms enough energy to overcome the electrical repulsion between the protons. Fusion requires temperatures of about 100 million Kelvin (approximately six times hotter than the sun's core).

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8 0
2 years ago
An electric drill rated at 400 W is connected to a 240V power line. How much current does it draw?
disa [49]

Answer:

1.67 A

Explanation:

Given that,

→ Power (P) = 400 W

→ Potential difference (V) = 240 V

→ Current (I) = ?

The amount of current drawn will be,

→ P = V × I

→ I = P/V

→ I = 400/240

→ I = 1.66666666667

→ [ I = 1.67 A ]

Hence, the current drawn 1.67 A.

8 0
3 years ago
Read 2 more answers
This is for physics, i need help fast!!
jarptica [38.1K]
Speed = distance / time
S= 40 000m / 5400s
S= 7.41m/s
7 0
3 years ago
2. A car accelerates uniformly from +10.0 m/s to +50.0 m/s over a distance of 225 m. How long did it take to go that distance? S
artcher [175]
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

It took 7.5 seconds


7 0
3 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


5 0
3 years ago
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