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mario62 [17]
3 years ago
8

What happened to the sedimentary rock layers that first formed over the ancient rock

Physics
1 answer:
aksik [14]3 years ago
3 0
They got turned over and now are on top
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A diverging lens (f1 = -12.0cm) is located 50.0 cm to the left of a converging lens (f2 = 34.0 cm). A 2.0 cm-tall object stands
pishuonlain [190]

Answer:

The final image relative to the converging lens is 34 cm.

Explanation:

Given that,

Focal length of diverging lens = -12.0 cm

Focal length of converging lens = 34.0 cm

Height of object = 2.0 cm

Distance of object = 12 cm

Because object at focal point

We need to calculate the image distance of diverging lens

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-12}

v=\infty

The rays are parallel to the principle axis after passing from the diverging lens.

We need to calculate the image distance of converging lens

Now, object distance is ∞

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{34}-\dfrac{1}{\infty}

v=34

The image distance is 34 cm right to the converging lens.

Hence, The final image relative to the converging lens is 34 cm.

5 0
3 years ago
30 POINTS! (Question is located in picture under graph)
harkovskaia [24]
Hi i think its E because the the numbers on both sides are to spread out and are not even one side is 4 and the other is 3
8 0
3 years ago
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Is the strange solid/liquid changing behavior of Oobleck the SAME as an ice cube melting?
Dmitrij [34]
I don’t think so because an ice cube melting needs heat and relies on temp while ooblecks transition from solid to quickly depends on force and speed
6 0
2 years ago
What is the force of gravity on an 100kg person standing on the earth
Bingel [31]
I think its 980.7
because 9.807 × 100
5 0
2 years ago
A 4.75 kg block is sent up a ramp inclined at an angle ????=31.5° from the horizontal. It is given an initial velocity ????0=15.
Colt1911 [192]

Answer:

d = 13.7 m

Explanation:

When block is moving upwards along the inclined plane

then the block is decelerated due to gravity as well as due to friction and speed of the block by which it is projected upwards is given

v_i = 15 m/s

deceleration caused to the block due to net force opposite to the motion is given as

F = - mg sin\theta - \mu mgcos\theta

a = \frac{F}{m}

a = -g(sin\theta + \mu cos\theta)

since block is sliding on the inclined plane

so here we can say that the coefficient of the friction must be kinetic friction here

a = -9.81(sin31.5 + 0.368 cos31.5)

a = - 8.2 m/s^2

now for finding the distance upto which it will stop is given as

v_f^2 - v_i^2 = 2 a d

0 - 15^2 = 2(-8.2) d

d = 13.7 m

8 0
2 years ago
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