A.) reference group
"A reference group includes individuals or groups that influence our opinions, beliefs, attitudes and behaviors. They often serve as our role models and inspiration"(study.com).
Answer:
La expansión no es más que el incremento con el tiempo de la distancia entre cualquier par de galaxias lejanas. Se suele utilizar para representar este hecho la analogía de un globo donde hemos pintado una serie de puntos a modo de galaxias.
Explanation:
Transmission of information in ANY form can be done digitally
or analoguely.
Beginning about 30 years ago, everything slowly started changing
to digital. Today, all commercial satellite communication, all optical
fiber communication, all internet communication, all computer
communication, all commercial cable communication, all commercial
television, and much of the telephone system, are all digital.
On your computer ... .pdf, .jpg, .mp3 etc. are all digital methods of
moving and storing information.
AM and FM radio are an interesting subject. They're all still analog.
They could easily be changed to all digital, and it would be a big
improvement, both for the broadcasters and for the listeners.
BUT ... every AM and FM radio that anybody has now would be
obsolete. Every single radio would either need to be replaced,
OR you'd need to add a digital decoder to every radio, like we
had to do with our TV sets a few years ago when television
suddenly became all digital. With AM and FM radios, the decoders
would be bigger, and would cost more, than most of the radios.
And that's why commercial radio broadcasting is still analog.
Answer:
Explanation:
A ball is thrown in forward direction by a person who is riding on the roof of the moving train.
-->If you neglected the air drag and relative to the ground, then the velocity of the ball is equal to the sum of the velocities of ball and the train.
-->Hence, the ball is moving faster.
-(b) Relative to the freight car, the ball moves at the same speed irrespective of train
Answer:
q2 = 9.02*10^{-4}C
Explanation:
To find the value of the other charge you use the Coulomb's law:
k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2
q1: charge 1 = 55*10^{-6}C
r: distance between charges = 90cm = 0.9m
F: electric force = 550N
By doing q2 the subject of the formula and replacing you obtain:
hence, the value of the other charge q2 is 9.02*10^{-4}C
