Answer:
The work done on the wagon is 37 joules.
Explanation:
Given that,
The force applied by Charlie to the right, F = 37.2 N
The force applied by Sara to the left, F' = 22.4 N
We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :
Work done on the wagon is given by the product of net force and displacement. It is given by :
W = 37 Joules
So, the work done on the wagon is 37 joules. Hence, this is the required solution.
Answer:
The first case requires more force to spin de bucket.
Explanation:
As we know, the centripetal force is directly proportional to the mass, the equation is given by:
The first case has a quarter more water than the second case, therefore the first case requires more force to spin de bucket.
I hope it helps you!