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creativ13 [48]
3 years ago
7

Which of the following is not a benefit of increased energy efficiency?

Physics
1 answer:
Rzqust [24]3 years ago
7 0
From what I can see it's D, I did this by simply examining the other answers and seeing that they are beneficial, so, from that information, this one must not be.
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A wheelbarrow is a complex machine that combines which simply marchines?
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It's most likely the combination of a bucket and the wheel. 
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I need help with the second one asap
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what I don't know show a question mark me as brainleast

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Solve the problems.
faltersainse [42]

Answer:

v= 1.911×10^8m/s

Explanation:

n=c/v

v=c/n

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7 0
2 years ago
1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.
AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}

Where;

v = The image distance from the lens

We get;

v = \dfrac{u \times f}{u - f}

Therefore;

v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0
2 years ago
What statement BEST describes a solid?
BARSIC [14]
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Gases: indefinite shape, indefinite volume
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x) Hope I helped! Which do you think it is?

5 0
3 years ago
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