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Alex787 [66]
3 years ago
8

How are cations formed

Chemistry
1 answer:
sweet [91]3 years ago
7 0

cations are formed when a metal loses electrons, and a nonmetal gains those electrons.

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How many TOTAL atoms are in the following molecule? NaHCO3
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NaHCO3 = No. of atoms are 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.

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4 Weathering Assessment
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How can you drop two eggs the fewest amount of times, without them breaking? Whoever gets this right I will mark them brainlyest
Alekssandra [29.7K]

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Okay well simply drop it from one inch on to the ground and it won't break and you could put it into a basket with bubble wrap.

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Well if you wrap the egg into bubble wrap a few times them put it into a basket (its your choice) then it won't break because the bubble wrap will just pop a few times but sometimes it depends on where you are dropping it from.

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3 years ago
Write balance complete molecular equation, ionic equation, and net ionic equations for the reactions that occur when each of the
AveGali [126]

<u>Answer:</u> The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.

<u>Explanation:</u>

The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

The net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:

Pb(NO_3)_2(aq)+Na_2S(aq)\rightarrow PbS(s)+2NaNO_3(s)

The ionic equation follows:

Pb^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)

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shepuryov [24]
Crystallization

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