The central maximum
extends to the first minimum on either side.
So the first minimum
occurs at <span>3cm / 2 = 1.5cm = 0.015m to the side from the center of the
central maximum. </span>
<span>Now using the formula,
λ = a(y/L)</span>
Where a is the width of
the slit, y = distance of first minimum from center, L = distance of screen
from slit, and λ = wavelength of the light that strikes a single slit at normal
incidence which is unknown here.<span>
a = L x λ/y
a = 1.80 m x (λ / 0.015 m)
a = 120 λ </span>
<span>Use the value of λ for
any light and you get the width of slit.</span>
Answer: B
Explanation:
The top number is its atomic number, also known as the number of protons in the atom.
The bottom number is the atomic mass, which is the sum of the number of protons and neutrons.
A current carrying wire placed perpendicular to a magnetic field experiences a force equal to
where
I is the current in the wire
L is the wire length
B is the intensity of the magnetic field
In our problem, the length of the wire is L=1.0 m, the magnetic field strength is B=0.20 T and the force exerted on the wire is F=0.60 N. If we re-arrange the equation and we plug these numbers into it, we find the current in the wire: