1)Baby bird cannot fly. Their mother has to feed \bf\underline{them}them
2. Vijay likes riding my bicycle. I sometimes lend \bf\underline{it}it to \bf\underline{him}him
3. Sooraj and I are brothers. \bf\underline{we\:both}weboth share the same bedroom.
4. Ravina isn't well. Dad is taking to the doctor. (No personal pronouns required)
<h3>5. My sister is a teacher. \bf\underline{She}She teaches Maths.</h3>
Infared = used by police
gamma = short wavelength
radio = largest wavelength
visible = only ones we can see
Answer:
1456 N
Explanation:
Given that
Frequency of the piano, f = 27.5 Hz
Entire length of the string, l = 2 m
Mass of the piano, m = 400 g
Length of the vibrating section of the string, L = 1.9 m
Tension needed, T = ?
The formula for the tension is represented as
T = 4mL²f²/ l, where
T = tension
m = mass
L = length of vibrating part
F = frequency
l = length of the whole part
If we substitute and apply the values we have Fri. The question, we would have
T = (4 * 0.4 * 1.9² * 27.5²) / 2
T = 4368.1 / 2
T = 1456 N
Thus, we could conclude that the tension needed to tune the string properly is 1456 N
