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2 years ago

Define position i am not sure?

1 answer:

5 0

A position is the point where something is located, as on a map, or the posture it's arranged in, such as an "upright position." Position has many meanings. ... As a verb it can mean lay, place, pose, or set.

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You launch a cannonball at an angle of 35° and an initial velocity of 36 m/s (assume y = y₁=

velikii [3]

Answer:

Approximately $4.2\; {\rm s}$ (assuming that the projectile was launched at angle of $35^{\circ}$ above the horizon.)

Explanation:

Initial vertical component of velocity:

$\begin{aligned}v_{y} &= v\, \sin(35^{\circ}) \\ &= (36\; {\rm m\cdot s^{-1}})\, (\sin(35^{\circ})) \\ &\approx 20.6\; {\rm m\cdot s^{-1}}\end{aligned}$ .

The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing $y_{1}$ is the same as the altitude $y_{0}$ at which this projectile was launched: $y_{0} = y_{1}$ .

Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is $20.6\; {\rm m\cdot s^{-1}}$ (upwards,) the vertical velocity right before landing would be $(-20.6\; {\rm m\cdot s^{-1}})$ (downwards.) The change in vertical velocity is:

$\begin{aligned}\Delta v_{y} &= (-20.6\; {\rm m\cdot s^{-1}}) - (20.6\; {\rm m\cdot s^{-1}}) \\ &= -41.2\; {\rm m\cdot s^{-1}}\end{aligned}$ .

Since there is no drag on this projectile, the vertical acceleration of this projectile would be $g$ . In other words, $a = g = -9.81\; {\rm m\cdot s^{-2}}$ .

Hence, the time it takes to achieve a (vertical) velocity change of $\Delta v_{y}$ would be:

$\begin{aligned} t &= \frac{\Delta v_{y}}{a_{y}} \\ &= \frac{-41.2\; {\rm m\cdot s^{-1}}}{-9.81\; {\rm m\cdot s^{-2}}} \\ &\approx 4.2\; {\rm s} \end{aligned}$ .

Hence, this projectile would be in the air for approximately $4.2\; {\rm s}$ .

8 0

1 year ago

Read 2 more answers

6. During an impact time casting 5 x 10-45 a gulf club exerts an average impar

Novay_Z [31]

Answer:

2.5 × 10-⁴¹ Ns

Explanation:

Impulse

I = F × t

I = 5000 N × 5 × 10-⁴⁵ s

I = 25 × 10-⁴² Ns

I = 2.5 × 10-⁴¹ Ns

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6 0

3 years ago

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

mamaluj [8]

Answer:

here try this! i hope this helps

Explanation:

There are many advantages when we compare strength training with other forms of training. For example, the biggest benefit would be the increase of muscle mass due to us using the muscle more and for harder movements than usual. Strength training can preserve the mass that we lose with age. Bones also get stronger when we train so they are harder to fracture. We get more joint flexibility from the movements we do. So things as arthritis can be avoided or at least feel better.

8 0

3 years ago

Read 2 more answers

At one atmosphere of pressure and 25°C, a hot air balloon has a volume of 4,000 liters. While still tied to the ground, the air

yawa3891 [41]

Based on the options given, the most likely answer to this query is C) 4577 liters.

Upon computation of the given variables the result seems to be 4577 L

Thank you for your question. Please don't hesitate to ask in Brainly your queries.

3 0

3 years ago

Read 2 more answers

A laboratory electromagnet produces a magnetic field of magnitude 1.38 T. A proton moves through this field with a speed of 5.86

Vladimir [108]

.Answer;

Using Fmax=qVB

F=(1.6*10^-19 C)(5.860*10^6 m/s)(1.38 T)

ANS=1.29*10^-12 N

2. Using Amax=Fmax/ m

Amax =(1.29*10^-12 N) / (1.67*10^-27 kg)

ANS=1.93*10^15 m/s^2*

3. No, the acceleration wouldn't be the same. Since The magnitude of the electron is equal to that of the proton, but the direction would be in the opposite direction and also Since an electron has a smaller mass than a proton

3 0

3 years ago