She knows that a magnesium ion has an electric field that pints away from the ion. What values should she use to complete her ta
1 answer:
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Explanation:
Given that,
Mass of the ball, m = 1.2 kg
Initial speed of the ball, u = 10 m/s
Height of the floor from ground, h = 32 m
(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :
v = -25.04 m/s (negative as it rebounds)
The impulse acting on the ball is equal to the change in momentum. It can be calculated as :
J = -42.048 kg-m/s
(b) Time of contact, t = 0.02 s
Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :
F = 0.8409 N
Hence, this is the required solution.
The question is incomplete! circuit figure is attached below and answer and explanation is provided below.
Answer:
Bulb_A = Bulb_B = Bulb_D and Bulb_C = 0.
Explanation:
What happens when switch is open?
When the switch is open Bulb_C is open circuited meaning that there is no way for the current to flow through it. This path offers infinite resistance to the current therefore, current will try to take a least resistance path that is through Bulb_B.
So eventually, when the switch is open the circuit becomes a simple series circuit with path From battery to Bulb_A to Bulb_B to Bulb_D to battery with Bulb_C = 0.
What happens in a series circuit?
We know that in a series circuit, there is only one path for the current to flow therefore, same current will flow through all the series Bulbs and their brightness will be same. Bulb_A = Bulb_B = Bulb_D
Brightness in a series circuit:
We also know know that in a series circuit, resistance gets summed up and voltage across each Bulb gets shared which results in less power dissipation that's why Bulbs connected in series appear dimmer as compared to when they are connected in parallel.
