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Inessa [10]
3 years ago
15

She knows that a magnesium ion has an electric field that pints away from the ion. What values should she use to complete her ta

ble
Physics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

B.X: 12 Y: 12 Z: 10

Explanation:

Ions are formed when an atom of an element that lacks stable configuration or octet configuration, looses or gains electrons to attain stability.

Magnesium atom contains 12 electrons, with an electron configuration of 2:8:2. Therefore, it requires to loose two electrons to attain stability, thus forming an ion. During ion formation, the number of protons and neutrons are not affected thus they do not change.

Therefore; Magnesium atom contain 12 electrons, 12 protons and 12 Neutrons. While magnesium atom contains 12 protons, 10 electrons, and 12 neutrons.

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you are making an observation that uses numbers.

Explanation:

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2 years ago
A charged particle enters a uniform magnetic field B with a velocity v at right angles to the field. It moves in a circle with p
alukav5142 [94]

A) d. 10T

When a charged particle moves at right angle to a uniform magnetic field, it experiences a force whose magnitude os given by

F=qvB

where q is the charge of the particle, v is the velocity, B is the strength of the magnetic field.

This force acts as a centripetal force, keeping the particle in a circular motion - so we can write

qvB = \frac{mv^2}{r}

which can be rewritten as

v=\frac{qB}{mr}

The velocity can be rewritten as the ratio between the lenght of the circumference and the period of revolution (T):

\frac{2\pi r}{T}=\frac{qB}{mr}

So, we get:

T=\frac{2\pi m r^2}{qB}

We see that this the period of revolution is directly proportional to the mass of the particle: therefore, if the second particle is 10 times as massive, then its period will be 10 times longer.

B) a. f/10

The frequency of revolution of a particle in uniform circular motion is

f=\frac{1}{T}

where

f is the frequency

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We see that the frequency is inversely proportional to the period. Therefore, if the period of the more massive particle is 10 times that of the smaller particle:

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6 0
3 years ago
Can you help me on this please
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The figure above shows 4forces 3N, 10N, 3√3N, and 6N acting on a particle P. The resultant of the four forces is.
Brilliant_brown [7]

As you gave no pic I took them on one lined

  • F_1=3N
  • F_2=10N
  • F_3=3root 3 N
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\\ \sf\longmapsto F_{net}=F_1+F_2\dots

\\ \sf\longmapsto F_{net}=3+10+6+3\sqrt{3}

\\ \sf\longmapsto F_{net}=19+3(1.732)

\\ \sf\longmapsto F_{net}=19+5.196

\\ \sf\longmapsto F_{net}=24.196N

6 0
2 years ago
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