-35 is the ans.wer.hope this hels
Answer:
≈ 0.144 m
Explanation:
Density is mass divided by volume:
D = M / V
Solving for volume:
V = M / D
Given M = 1.2 kg and D = 400 kg/m³:
V = 1.2 kg / (400 kg/m³)
V = 0.003 m³
Volume of a cube is the side length cubed:
V = s³
Therefore:
s³ = 0.003 m³
s ≈ 0.144 m
Round as needed.
ANSWER :
(A) AT RIGHT ANGLES TO THE DIRECTION THE WAVE TRAVELS.
EXPLANATION :
TRANSVERSE WAVES IS THAT IN WHICH THE PARTICLES VIBRATE WITH AN UP-AND-DOWN MOTION. THE PARTICLES IN A TRANSVERSE WAVE MOVE ACROSS OR PERPENDICULAR TO THE DIRECTION THAT THE WAVE IS TRAVELING OR AT RIGHT ANGLES TO THE DIRECTION THE WAVE TRAVELS.
Answer:
b. 12.5 mAs, 70 kVp
Explanation:
The given parameter are;
The initial exposure factors := 10 mAs and 70 kVp
The initial Grid Ratio, G.R.₁ = 8:1
The Grid Ratio with which the radiographer desires to increase the scatter absorption, G.R.₂ = 12:1
Given that the lead content in the 12:1 grid, is higher than the lead content in 8:1 grid and that 12:1 grid needs more mAs to compensate, and provides a higher image contrast, the amount of extra mAs is given by the Grid Conversion Factors, GCF, as follows;
The GCF for G.R. 8:1 = 4
The GCF for G.R. 12:1 = 5
Therefore, given that the mAs used by the radiographer for 8:1 Grid Ratio is 10 mAs, the mAs required for a G.R. of 12:1 in order to maintain the same exposure is given as follows;
mAs for G.R. of 12:1 = 10 mAs × 5/4 = 12.5 mAs
Therefore the new exposure factors are;
12.5 mAs, 70 kVp
