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tatuchka [14]
3 years ago
12

8. Mark is sitting in a chair, legs out in front of him resting on an ottoman. His knees are.....

Physics
2 answers:
Burka [1]3 years ago
7 0
Yep! If legs are in front of him, then his legs are straight in perpendicular direction, so his knees are making 180 degree of angle..

Hope it helped.
anyanavicka [17]3 years ago
5 0
His knees are flat in front of him or 180 degrees, i hope that answered your question   
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Answer:

Protons and electrons are charged particles. Neutrons have no charge.

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3 years ago
A plastic rod 1.3 m long is rubbed all over with wool, and acquires a charge of -3e-08 coulombs. we choose the center of the rod
Anestetic [448]
(a) The plastic rod has a length of L=1.3m. If we divide by 8, we get the length of each piece:
L/8=1.3m/8=0.1625 m

(b) The center of the rod is located at x=0. This means we have 4 pieces of the rod on the negative side of x-axis, and 4 pieces on the positive side. So, starting from x=0 and going towards positive direction, we have: piece 5, piece 6, piece 7 and piece 8. Each piece is 0.1625 m long. Therefore, the center of piece 5 is at 0.1625m/2=0.0812 m. And the center of piece 6 will be shifted by 0.1625m with respect to this:
c_6 = 0.0812m+0.1625m=0.2437 m

(c) The total charge is Q=-3 \cdot 10^{-8}C. To get the charge on each piece, we should divide this value by 8, the number of pieces:
Q/8=-3\cdot 10^{-8}C/8=-3.75\cdot 10^{-9}C

(d) We have to calculate the electric field at x=0.7 generated by piece 6. The charge on piece 6 is the value calculated at point (c):
q= -3.75\cdot 10^{-9}C
If we approximate piece 6 as a single  charge, the electric field is given by
E=k_e  \frac{q}{d^2}
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E= 8.99\cdot 10^9 Nm^2C^{-2} \frac{-3.75\cdot 10^9 C}{(0.2437m-0.7m)^2} =-161.9 V/m
poiting towards the center of piece 6, since the charge is negative.

(e) missing details on this question.
5 0
3 years ago
In every trench over 4 feet (1.2 m) deep, there must be an exit every​
ss7ja [257]

Explanation:

25 ft I believe that this is the best answer

5 0
3 years ago
A solid nonconducting sphere of radiusRcarries a chargeQdistributed uniformly throughout itsvolume. At a certain distancer1(r1&l
lara [203]

Answer:

E' = \frac{1}{8} E

Explanation:

Given data:

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second case

Distance of electric field from centre of sphere is r_1 < 2R

Electric field at r_1< 2R

E' = \frac{kQr_1}{8R^3}

so, we have

E' = \frac{1}{8} E

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Answer:

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Explanation:

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