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Ilia_Sergeevich [38]
3 years ago
15

Why do girls develop differently?

Chemistry
2 answers:
Deffense [45]3 years ago
7 0
Different hormones then males.
Slav-nsk [51]3 years ago
7 0
Girls have estrogen and boys have testosterone. that's why transgender girls take estrogen to develop more femininely, and transgender boys take testosterone to develop more masculinely.
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During bromination using NBS, the addition product is not observed because the rate of addition is _______than the rate of the c
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Answer:

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Explanation:

NBS is used in place of Br2 during bromination because the use of Br2 tends to result in the formation of a large concentration of the addition product.  This is because, the Br2 interacts with the double bond to yield only the dibromide (addition product).

The usefulness of NBS lies in the fact that it provides a lower concentration of Br2, and such that the rate addition is slower than the chain propagation steps. Only the monobromination product is observed

The low concentration of Br2 allows the free-radical reaction to out-compete the alkene addition reaction.

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Which element would be the most conductive and
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Malleability described the property of physical deformation under some compressive stress; a malleable material could, for example, be hammered into thin sheets. Malleability is generally a property of metallic elements: The atoms of elemental metals in the solid state are held together by a sea of indistinguishable, delocalized electrons. This also partially accounts for the generally high electrical and thermal conductivity of metals.

In any case, only one of the elements listed here is a metal, and that’s copper. Moreover, the other elements (hydrogen, neon, and nitrogen) are gases under standard conditions, and so their malleability wouldn’t even be a sensible consideration.
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What state of matter is dubnium
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At room temperature, it is a solid state of matter. hope this helps, have an amazing day :)
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Review Problem 5.040 For each reaction, identify in order the substance oxidized, the substance reduced, the oxidizing agent, an
alexandr402 [8]

Answer:

A. The correct option is: Cu; H₂SO₄; H₂SO₄; Cu

B. The correct option is: SO₂; HNO₃; HNO₃; SO₂

C. The correct option is: Zn; H₂SO₄; H₂SO₄; Zn

D. The correct option is: I₂; HNO₃; HNO₃; I₂

Explanation:

A chemical reaction that involves the simultaneous transfer of electrons between two chemical species is known as the redox reaction.

In this reaction, a species that gains electrons, thus getting reduced is called the <u>oxidizing agen</u>t. Whereas, species that loses electrons, thus getting oxidized is called the<u> reducing agent</u>.

<u>Oxidation</u> refers to an increase in the oxidation state and <u>reduction</u> refers to a decrease in the oxidation state.

A. Cu + 2H₂SO₄ → CuSO₄ + SO₂ +2H₂O

In this reaction, Cu goes from 0 in Cu to +4 oxidation state in CuSO₄ and thus gets oxidized. Whereas, S goes from +6 in H₂SO₄ to +4 oxidation state in SO₂ and thus gets reduced. Therefore, H₂SO₄ is the oxidizing agent and Cu is the reducing agent.

<u>The correct option is: Cu; H₂SO₄; H₂SO₄; Cu</u>

B. 3SO₂ + 2HNO₃ + 2H₂O → 3H₂SO₄ + 2NO

In this reaction, S goes from +4 in SO₂ to +6 oxidation state in H₂SO₄ and thus gets oxidized. Whereas, N goes from +5 in HNO₃ to +2 oxidation state in NO and thus gets reduced. Therefore, HNO₃ is the oxidizing agent and SO₂ is the reducing agent.

<u>The correct option is: SO₂; HNO₃; HNO₃; SO₂</u>

C. 5H₂SO₄ + 4Zn → 4ZnSO₄ + H₂S +4H₂O

In this reaction, Zn goes from 0 in Cu to +2 oxidation state in ZnSO₄ and thus gets oxidized. Whereas, S goes from +6 in H₂SO₄ to -2 oxidation state in H₂S and thus gets reduced. Therefore, H₂SO₄ is the oxidizing agent and Zn is the reducing agent.

<u>The correct option is: Zn; H₂SO₄; H₂SO₄; Zn</u>

D. I₂ + 10HNO₃ → 2HIO₃ + 10NO₂ + 4H₂O

In this reaction, I goes from 0 in I₂ to +5 oxidation state in HIO₃ and thus gets oxidized. Whereas, N goes from +5 in HNO₃ to +4 oxidation state in NO₂ and thus gets reduced. Therefore, HNO₃ is the oxidizing agent and I₂ is the reducing agent.  

<u>The correct option is: I₂; HNO₃; HNO₃; I₂</u>

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