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3 years ago

Number of H in 3(NH4)2Cro4

Chemistry

1 answer:

zlopas [31]3 years ago

7 0

The number of H atoms in 3(NH₄)₂CrO₄ = 24

<h3>Further explanation </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

Subscripts in the chemical formula indicate the number of atoms

The compound of 3(NH₄)₂CrO₄ ( 3 molecules of (NH₄)₂CrO₄ ) :

Number of H :

$\tt 4\times 2(subscript)\times 3(coefficient,number~of~molecules)=24~atoms$

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3 years ago

A teacher divides her class into four groups. She assigns

babunello [35]

Group C : 32.1°C , 31.9°C, 31.8°C makes the most precise measurements of the object's temperature.

Precision :The degree of similarity between study results of the experiment if they were performed today under comparable conditions.

If repeated measurements yield similar results, the measurement is considered precise (or repeated surveys).

It means how closely all the results are related .

Therefore, there should be less difference between the measurements of all the results.

In option (a) , there is a difference of 1° in all the results.

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2 years ago

PLEASE HELP!!!!

coldgirl [10]

Answer:

1.2 liters.

Explanation:

Focus on the 4th digit: that's the ones column. The 3rd digit is the decimal place, just be sure to round up.

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3 years ago

Calculate the molarity of a solution made by dissolving 4.0 g of calcium bromide, CaBr2, in enough water to give 200 mL of solut

Troyanec [42]

Answer:

0.1 M

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Molarity = number of moles / litres of solution.

4 g of calcium bromide = 0.02 mol

(found by dividing 4 g by the atomic mass of CaBr2, which is 199.886)

200 mL of solution = 0.2 litres

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3 years ago

If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?

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Silicon is the element having a mass of 28.09 g

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Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 $\times$ 10^23 atoms. One mole of each element can produce one mole of compound.

The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 $\times$ 10^23).

Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 $\times$ 10^23 atoms of an element are equal to the average atomic mass of that element.

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3 years ago