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cestrela7 [59]
3 years ago
15

Balance the following equation. use “1” when needed __Ga2o3->__Ga +__02

Chemistry
1 answer:
Sloan [31]3 years ago
7 0

Answer:

2Ga2O3 = 4Ga + 3O2

Explanation:

You need to balance out the equation by making sure there are the same number of elements on each side.

Ga   -    4 on each side

O    -    6 on each side

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If a shell can hold a maximum of 32 electrons, what is the value of n?
sweet [91]

Answer:

The value of N would be 4.

Explanation:

The equation would be 2n^x = 32 and therefore, 4.

4 0
3 years ago
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An oxide of phosphorus contains 56.4% phosphorus and 43.6% oxygen. It's relative molecular mass is 220. Find both the empirical
sladkih [1.3K]
Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O

converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5

1 P and 2 oxygens.
PO2 -> the empirical formula

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7 0
3 years ago
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Explain how camaflouge is an adaption
suter [353]
Camouflage is an adaptation because you change yourself for better survival.

For example, an Octopus can change the color of its body to blend in with its surroundings which makes it hard for predators and prey to see them.
3 0
3 years ago
Describe the difference in structure between beH2 and CaH2
katen-ka-za [31]
Hello!

BeH₂ is a linear molecule, while CaH₂ is an angular molecule.

The difference between these two molecules is given by the number of electrons they have. Be is in the 2nd period of the Periodic table, and the ion Be⁺² doesn't have any free electron pairs when bonding to H. Ca is in the 4 period of the periodic table, meaning that it has more electrons, and the ion Ca⁺² has two free electron pairs when bonding to H that makes the molecule angular by pushing the bonds at an angle by sterical hindrance.  

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7 0
4 years ago
g Identify limiting reactants (mole ratio method). Close Problem Identify the limiting reactant in the reaction of bromine and c
love history [14]

Answer:

(i) Cl₂ is a limiting reactant

(ii) The amount of excess reactant = 4.8 g

Explanation:

                             Br₂(g) + Cl₂(g) → 2 BrCl(g) ---------------------------(i)

Calculation of no. of moles

                            Moles of Br_{2}  = \frac{weight}{Molecular weight} = \frac{29.7}{160} =0.18

                            Moles of Cl_{2}  =\frac{11.2}{71}  = 0.15 mole

Using mole ratio method to find the limiting reactant and Excess reactant.

                            \frac{Mole}{Stoichiometry} (for Br_{2} ) = \frac{0.18}{1}  = 0.18

                            \frac{Mole}{Stoichiometry}(for Cl_{2}) =\frac{0.15}{1}=0.15

So Cl_{2} is a limiting reactant and Br₂ is excess reactant.

The amount of excess reactant = 0.18 - 0.15 = 0.03 mole = 4.8 g

5 0
4 years ago
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