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pickupchik [31]
3 years ago
14

Becky is a flower gardener. Her plants need a rich soil, full of nutrients, to grow. Propose a detailed plan of how Becky can de

termine if her soils are fit for growing flowers
Chemistry
2 answers:
svp [43]3 years ago
6 0
For the answer to the question above, Becky should consider <span>the climate of the native environment in which the plant is found then compare it the to the climate in which she plans on growing the flowers, similar climates will produce some similarities between soils. She should research on what type of environment the plant was suitable. Because like strawberries can't be grown on desert temperature and soil.</span>
WINSTONCH [101]3 years ago
5 0

Answer:

In order to grow a plant one should first look and compare the climate of the local environment in which the plant grows with the climate in which the person is planning to grow the plant. Thus, in the given case, Becky should do more examinations on the kind of environment and the kind of soil in which the flower is grown generally. By finding the kind of soil, one should perform some brisk assessment on the structure and composition of the soils that will permit one to find that whether or not the planting location is suitable for the growth of the flower.  

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Im the only noble gas with 2 electrons
iris [78.8K]

Answer:

Helium

Explanation:

8 0
3 years ago
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Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.
tamaranim1 [39]

Answer:

1500kg/m^3

Explanation:

Formula:

d=m/v

Given:

m=1.5kg

v=1000cm^3

(The side length of a cube is always equal to the others)

Required:

d=?

Solution:

d=m/v

d=1.5kg/1000cm^3

d=1.5kg/0.001m^3

d=1500kg/m^3

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3 0
3 years ago
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
3 years ago
How do I do question number 4?
lisabon 2012 [21]
I hope you understood
hit me up if you have any other questions :>

6 0
3 years ago
would a cloud or a rock be more dense? PLSSSSSS HELP PLSSS I WILL MARK BRAINLIEST AND ANSWER SOME OF YOUR QUESTIONS
QveST [7]
A rock is definitely more dense. If you were to put a cloud in water it would float/stay above it and a rock would sink to the bottom
6 0
3 years ago
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