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pickupchik [31]
3 years ago
14

Becky is a flower gardener. Her plants need a rich soil, full of nutrients, to grow. Propose a detailed plan of how Becky can de

termine if her soils are fit for growing flowers
Chemistry
2 answers:
svp [43]3 years ago
6 0
For the answer to the question above, Becky should consider <span>the climate of the native environment in which the plant is found then compare it the to the climate in which she plans on growing the flowers, similar climates will produce some similarities between soils. She should research on what type of environment the plant was suitable. Because like strawberries can't be grown on desert temperature and soil.</span>
WINSTONCH [101]3 years ago
5 0

Answer:

In order to grow a plant one should first look and compare the climate of the local environment in which the plant grows with the climate in which the person is planning to grow the plant. Thus, in the given case, Becky should do more examinations on the kind of environment and the kind of soil in which the flower is grown generally. By finding the kind of soil, one should perform some brisk assessment on the structure and composition of the soils that will permit one to find that whether or not the planting location is suitable for the growth of the flower.  

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Which compound when dissolved in water is an Arrhenius acid? A) CH3OH B) HCl C) NaCl D) NaOH
Rudik [331]
I believe the answer is B because it donates H+ ions
6 0
3 years ago
Read 2 more answers
What is the pH of a solution within a solution with pH = 4.50? [H +] = 3.25×10-6 M?
Lisa [10]

Answer: 5.48

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution.

Mathematically, pH = - log(H+)

where H+ represent the concentration of hydrogen ion

So, to get the pH of the solution with [H +] = 3.25×10-6 M:

Apply, pH = -log(H+)

pH = - log (3.25×10-6 M)

pH = - ( -5.48)

(Note that the minus signs will cancel out each other)

Therefore pH = 5.48

Now we know that the pH of the solution with hydrogen ion concentration of 3.25×10-6 M is 5.48 (i.e slightly acidic)

Thus, we can finally say 5.48 is the pH of the solution within a solution with pH = 4.50

6 0
4 years ago
A student added 5 grams of calcium chloride, a white solid substance, to 15 grams of water at 220 C. Several observations were m
umka21 [38]

Answer:

D

Explanation:

A The calcium chloride dissolves in solution

B The mass of the solution totals 20 g

C The temperature of the solution is 35 degrees

D The solution became lighter in color

The correct answer would be that <u>the solution became lighter in color.</u>

An increase in temperature can also be considered a sign of a chemical reaction but in this case, the dissolution of calcium chloride in water is in itself exothermic.

A change in the mass of the final solution could also be considered a sign of a chemical reaction but in this case, the total mass equals the addition of the individual masses of the reactant.

The dissolution of calcium chloride in water is not enough as evidence of a chemical reaction. Dissolution can be a physical change of which, the evaporation of the water would retrieve the solute.

<em>A change in color, however, is one of the evidence to establish that a chemical reaction has occurred.</em>

The correct option is D.

4 0
3 years ago
Pitchblende is ore of _____.<br><br> plutonium<br> curium<br> uranium<br> radium
lisabon 2012 [21]

Answer:

I believe it is radium

Explanation:

8 0
3 years ago
For the following reaction, 8.70 grams of benzene (C6H6) are allowed to react with 13.7 grams of oxygen gas. benzene (C6H6) (l)
artcher [175]

Answer:

Maximum amount of carbon dioxide that can be formed → 7.52 g

Limiting reactant  → O₂

Amount of the excess reagent, after the reaction occurs → 12.9 g

Explanation:

We determine the reaction. This is a combustion:

2C₆H₆ (l) + 15O₂ (g) → 6CO₂(g) + 6H₂O (g)

We need to determine the limting reactant so we convert the mass to moles:

8.70 g. 1mol / 78g = 0.111 moles of benzene

13.7 g . 1mol / 32g = 0.428 moles of oxygen

Ratio is 2:15. 2 moles of benzene react with 15 moles of O₂

Then, 0.111 moles of benzene may react with (0.111 .15) /2 = 0.832 moles of O₂

We have 0.428 moles but we need 0.832 moles for the complete reaction, so there are (0.832 - 0.428) = 0.404 moles remaining. Oxygen is the limiting reactant. We work now, with the reaction:

15 moles of O₂ can produce 6 moles of CO₂

So, 0.428 moles of O₂ may produce (0.428 . 6)/ 15 = 0.171 moles of CO₂

We convert the moles to mass → 0.171 mol . 44g / 1mol = 7.52 g

This is the maximum amount of carbon dioxide that can be formed

We convert the mass of the limiting reactant that remains after the reaction is complete → 0.404 mol . 32g / 1mol = 12.9 g of O₂

7 0
3 years ago
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