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2 years ago

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A circle in the xy-plane has diameter 9.8 cm. A magnetic field of strength 3.4 T is oriented at an angle of 23° to the z-axis, a

line that is perpendicular to the xy-plane. What is the magnetic flux through the circle?
0.26 Wb
0.98 Wb
0.024 Wb
0.47 Wb

1 answer:

Evgesh-ka [11]2 years ago

4 0

<span>Let the area vector point along the z-axis:
Flux = B.A = B*cos(23)*pi*r^2 </span>

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Answer:

t = 4 s

Explanation:

As we know that the particle A starts from Rest with constant acceleration

So the distance moved by the particle in given time "t"

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$d = 0 + \frac{1}{2}(65.5)t^2$

$d_1 = 32.75 t^2 cm$

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now we know that B is already 349 cm down the track

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2 years ago

Is it proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinde

Gelneren [198K]

Answer:

No, it is not proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinder.

Explanation:

A cylinder is said to be infinitely long when is of a sufficient length. Also, when the diameter of the cylinder is relatively small compared to the length, it is called infinitely long cylinder.

Cylindrical rods can also be treated as infinitely long when dealing with heat transfers at locations far from the top or bottom surfaces. However, it not proper to treat the cylinder as being infinitely long when:

* When the diameter and length are comparable (i.e have the same measurement)

When finding the temperatures near the bottom or top of a cylinder, it is NOT PROPER TO USE AN INFINITELY LONG CYLINDER because heat transfer at those locations can be two-dimensional.

Therefore, the answer to the question is NO, since it is not proper to use an infinitely long cylinder when finding temperatures near the bottom or top of a cylinder.

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Then it would be C if D has been eliminated

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2 years ago

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Answer

Given,

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Radius of circular orbit,R = 1.04 x 10¹¹ m

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$\omega = 1.864\times 10^{-7}\ rad/s$

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$v = r \omega = 1.04\times 10^{11}\times 1.864 \times 10^{-7}$

v = 1.94 x 10⁴ m/s

c) centripetal acceleration magnitude

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2 years ago

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Resistance ∞ (proportional) length
resistance ∞ 1/ area

therefore,
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resistance = (resistivity*length )/ area
resistivity = (resistance * area ) / length
= (3 * 45) / 3 = 135/3 = 45 Ωm

in short your answer is 45 Ωm

4 0

3 years ago