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Paul [167]
3 years ago
12

Determine the number of milliliters in a volume of 2.81 fluid ounces

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
83.1 milliliters , have a good day
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Calculate the maximum deceleration (in m/s2) of a car that is heading down a 14° slope (one that makes an angle of 14° with the
lesya [120]

The question is incomplete. Here is the complete question.

Calculate the maximum deceleration  of a car that is heading down a 14° slope (one that makes an anlge of 14° with the horizontal) under the following road conditions. You may assum that the weight of the car is evenlydistributed on all four tires and that the sttic coefficient of friction is involved - that is, the tires are not allowed to slip during the deceleration. (Ignore rolling) Calculate for a car: (a) On a dry concrete. (b) On a wet concrete. (c) On ice, assuming that μs = 0.100, the same as for shoes on ice.

Answer: (a) a = - 11.05 m/s²; (b) a = - 10.64 m/s²; (c) a = - 9.84m/s²

Explanation: The image in the attachment describe the forces acting on the car. Observing that, we know that:

F_{net} = - W_x - f_s

The W_x is a x-component of force due to gravity (W) and, in this case, is given by: W_x = W.sin(14)

W is described as: W = m.g

Force due to friction (f_s) is given by: f_s = μs.N

N is the normal force and, in the system, is equivalent of W_y, so:

W_y = m.g.cos(14)

Therefore, the formula will be:

F_{net} = - W_x - f_s

m.a = - (m.g.sin14) - (μs.mg.cos14)

a = - g (sin14 + μscos 14)

a) For dry concrete, μs = 1:

a = - g (sin14 + μscos 14)

a = - 9.8 (sin14 + 1.cos14)

a = - 11.05 m/s²

b) For wet concrete, μs = 0.7:

a = - g (sin14 + μscos 14)

a = - 9.8 (sin 14 + 0.7.cos14)

a = - 10.64 m/s²

c) For ice, μs = 0.1:

a = - g (sin14 + μscos 14)

a = - 9.8 (sin14 + 0.1cos14)

a = - 9.84 m/s²

3 0
3 years ago
Spiderman, whose mass is 72.0 kg, is dangling on the free end of a 11.0-m-long rope, the other end of which is fixed to a tree l
Dmitry_Shevchenko [17]

i think that they answered this in the movie, but his mass cancels out and he is left with his core strength and gravity

∵∫∑⊥

6 0
3 years ago
What constant acceleration is required to increase the speed of a car from 27 mi/h to 53 mi/h in 3s?
mario62 [17]

Answer:

8.87 m/s^2  

Explanation:

Acceleration is change in velocity over a change in time

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7 0
1 year ago
While standing on a bridge 15 m above the ground, you drop a stone from rest. When the stone has fallen 3.2 m, you throw a secon
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Answer:

11.3 m/s

Explanation:

First, find the time it takes for the first stone to fall 3.2 m.

Given:

Δy = 3.2 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(3.2 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.81 s

Next, find the time for the first stone to land.

Given:

Δy = 15 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(15 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.75 s

The difference in time is 1.75 s − 0.81 s = 0.94 s.  Find the initial velocity needed for the second stone to land after that amount of time.

Given:

Δy = 15 m

a = 9.8 m/s²

t = 0.94 s

Find: v₀

Δy = v₀ t + ½ at²

(15 m) = v₀ (0.94 s) + ½ (9.8 m/s²) (0.94 s)²

v₀ = 11.3 m/s

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3 years ago
If the baseball and the plastic ball were moving at the same speed which ball would hit a bat harder
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The baseball because it has a greater mass and would go farther because it don't have holes for the air to go through and slow it down
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