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Paul [167]
3 years ago
12

Determine the number of milliliters in a volume of 2.81 fluid ounces

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
83.1 milliliters , have a good day
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An m = 7.25 kg mass is suspended on a string which is pulled upward by a force of F = 76.7 N as shown in the figure. If the upwa
GenaCL600 [577]

The velocity after 30s would be 38. 99 m/s

<h3>How to calculate the velocity</h3>

Using the formula

F = m Δ V/ t

Where, F = force = 76. 7N

m = mass = 7. 25kg

Δv = change in velocity= V2 - V1 and V1 = 2. 25 m/s

t = time = 3. 50s

76. 7 = 7. 25 × (v2 - 2. 25) / 3. 50

76. 7 = 2. 07 × (v2 - 2. 25)

make v2 subject of formula

v2 - 2. 25 = 76. 07 ÷ 2. 07

v2 = 36. 74 + 2. 25

v2 = 38. 99 m/s

Thus, the velocity after 3. 50s would be 38. 99 m/s

Learn more about change in velocity here:

brainly.com/question/10962624

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4 0
2 years ago
In a Millikan experiment, a droplet of mass 4.7 x 10^-15 kg floats in an electric field of 3.20 x 104 N/C.
andrezito [222]

Answer:

a. The force of gravity on the droplet is approximately 4.606 × 10⁻¹⁴ Newtons

b. The electric force that balances the force of gravity is approximately -4.606 × 10⁻¹⁴ Newtons

c. The excess charge is approximately -1.439375 × 10⁻¹⁸ C

d. There are approximately 9 excess electrons on the droplet

Explanation:

The parameters of the Millikan experiment are;

The mass of the droplet, m = 4.7 × 10⁻¹⁵ kg

The electric field in which the droplet floats, E = 3.20 × 10⁴ N/C

a. The force of gravity on the droplet, F = The weight of the droplet, W = m × g

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

W = 4.7 × 10⁻¹⁵ kg × 9.8 m/s² = 4.606 × 10⁻¹⁴ Newtons

∴ The force of gravity on the droplet = W = 4.606 × 10⁻¹⁴ Newtons

b. The electric force that balances the force of gravity, F_v = -W = -4.606 × 10⁻¹⁴ Newtons

c. The excess charge is given as follows;

F_v = q·E

∴ The electric force that balances the force of gravity, F_v = q·E =  -4.606 × 10⁻¹⁴ N

q·E =  -4.606 × 10⁻¹⁴ N

q =  -4.606 × 10⁻¹⁴ N/E

∴ q = -4.606 × 10⁻¹⁴ N/(3.20 × 10⁴ N/C) ≈ -1.439375 × 10⁻¹⁸ C

The excess charge, q ≈ -1.439375 × 10⁻¹⁸ C

d. The charge of one electron, e = 1.602176634 × 10⁻¹⁹C

The number of excess electrons in the droplet, n, is given as follows;

n = 1.439375 × 10⁻¹⁸ C/(1.602176634 × 10⁻¹⁹C) = 8.98387212405 electrons

∴ n ≈ 9 electrons.

7 0
3 years ago
Which type of central heating system involves fans and ducts to circulate warm air?
satela [25.4K]
Forced-Air would be the type of central heating system 
3 0
3 years ago
Read 2 more answers
Two students race up a flight of steps together. "Student A" reaches the top of the steps 2 seconds ahead of
oksano4ka [1.4K]
Um student a because they were there a few seconds ahead
3 0
3 years ago
An 1100kg car reached 30m/s in 9s from rest. What force did the engine provide?
malfutka [58]

Answer:

≅3666.67 N

Explanation:

Use Newton's 2nd law, F = ma where F=force applied, m = mass of the object,

a = acceleration acquired by the object.

a= (v-u)/t where v = final velocity, u = initial velocity and t = time taken

calculate a = (30-0)/9 ≅ 3.33 m/s2

Then F = 1100×a = 3666.67 N

3 0
3 years ago
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