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Tju [1.3M]
3 years ago
13

Consider an alien on a planet with an acceleration of gravity equal to 20 m/sec^2. If the alien's mass is 10 kg, how much does t

he alien weigh?
Physics
1 answer:
mr_godi [17]3 years ago
6 0

Answer:

the weight of alien is 200 newtons

Explanation:

The computation of the alien weight is shown below:

Given that

Acceleration = 20m/sec^2

And, the mass is 10 kg

So, the weight of alien is

= 20 × 10

= 200 newtons

hence, the weight of alien is 200 newtons

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30km. 24 the first two hours and 6 the half hour
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A 0.00275 kg air‑inflated balloon is given an excess negative charge q1 =−3.50×10−8 C by rubbing it with a blanket. It is found
kati45 [8]

Answer:

1)  \rm q_2 is<u> positive.</u>

<u></u>

2) \rm q_2=4.56\times 10^{-10}\ C.

Explanation:

<h2><u>Part 1:</u></h2>

<u></u>

The charged rod is held above the balloon and the weight of the balloon acts in downwards direction. To balance the weight of the balloon, the force on the balloon due to the rod must be directed along the upwards direction, which is only possible when the rod exerts an attractive force on the balloon and the electrostatic force on the balloon due to the rod is attractive when the polarities of the charge on the two are different.

Thus, In order for this to occur, the polarity of charge on the rod must be positive, i.e., \rm q_2 is <u>positive.</u>

<u></u>

<h2><u>Part 2:</u></h2>

<u></u>

<u>Given:</u>

  • Mass of the balloon, m = 0.00275 kg.
  • Charge on the balloon, \rm q_1 = -3.50\times 10^{-8}\ C.
  • Distance between the rod and the balloon, d = 0.0640 m.
  • Acceleration due to gravity, \rm g = 9.81\ m/s^2.

In order to balloon to be float in air, the weight of the balloom must be balanced with the electrostatic force on the balloon due to rod.

Weight of the balloon, \rm W = mg = 0.00275\times 9.81=2.70\times 10^{-2}\ N.

The magnitude of the electrostatic force on the balloon due to the rod is given by

\rm F_e = \dfrac{1}{4\pi \epsilon_o}\dfrac{|q_1||q_2|}{d^2}.

\rm \dfrac{1}{4\pi \epsilon_o} is the Coulomb's constant.

For the elecric force and the weight to be balanced,

\rm F_e = W\\\dfrac{1}{4\pi \epsilon_o}\dfrac{|q_1||q_2|}{d^2}=W\\8.99\times 10^9\times \dfrac{3.50\times10^{-8}\times |q_2| }{0.0640^2}=2.70\times 10^{-2}\\|q_2| = \dfrac{2.70\times 10^{-2}\times 0.00640^2}{8.99\times 10^9\times 2.70\times 10^{-7}}=4.56\times 10^{-10}\ C.

3 0
3 years ago
2. Find the time taken by the bus to reach the stop. need only group B, 2 answer
Molodets [167]

Answer:

t = 2 seconds

Explanation:

In 2nd question, the question is given the attached figure.

Initial speed of the bus, u = 0

Acceleration of the bus, a = 8 m/s²

Final speed, v = 16 m/s

We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :

a=\dfrac{v-u}{t}

t is time taken

t=\dfrac{v-u}{a}\\\\t=\dfrac{16-0}{8}\\\\t=2\ s

The bus will take 2 seconds to reach the stop.

3 0
3 years ago
People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Whitepunk [10]
The answer I believe is c
Explanation
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A person pushes a 10 kg box from rest and accelerates it to a speed of 4 m/s with a constant force. If the box is pushed for a t
lutik1710 [3]

The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration <em>a</em> is such that

4 m/s = <em>a</em> (2.5 s)   →   <em>a</em> = (4 m/s) / (2.5 s) = 1.6 m/s²

Then the force applied to the box has a magnitude <em>F</em> such that

<em>F</em> = (10 kg) (1.6 m/s²) = 16 N

7 0
3 years ago
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