Answer:
The value is 
Explanation:
From the question we are told that
The total time of flight is
Generally from kinematic equation

So v is the velocity at maximum height and the value is v = 0 m/s
So

=> 
Here u is the initial velocity of the dart as it leaves that gun
Gnerally the horizontal range of the dart is mathematically represented as

For maximum horizontal range the value of
So

=> 
Antelope: uniform motion => V = d/t => d = Vt = 7m/s * t
Lion: uniformly accelerated motion, with initial velocity = 0 => d = [1/2]a*t^2 = [1/2]*[5m/s^2]*t^2
7*t = 2.5*t^2=> 2.5t^2 - 7t =0 => t(2.5t - 7) = 0
2.5t - 7 = 0 => t = 7/2.5 = 2.8 m/s^2
Answer:
The object would weight 63 N on the Earth surface
Explanation:
We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

Now, if the body is on the surface of the Earth, its weight (w) would be:

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

Answer:
Smaller refractive power
Explanation:
The refractive power of an eye is the extent to which it can converge or diverge the light rays.
Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.
A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.
Thus the near point also increases and the refractive power becomes smaller.
An object moving in a circular path has centripetal acceleration. <em>(A)</em>