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harkovskaia [24]
3 years ago
8

A(n) ________ is a low layer of dark gray clouds that produces precipitation.

Physics
2 answers:
Katen [24]3 years ago
7 0

Answer:

nimbostratus

Explanation:

enot [183]3 years ago
5 0
Nimbostratus clouds cause precipitation
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A student buys a plastic dart gun and tries to find the maximum horizontal range. The student shoots the gun straight up and it
ryzh [129]

Answer:

The value is R_{max}  = 33.54 \  m

Explanation:

From the question we are told that

    The total time of flight is  t =  3.7 \  s

Generally from kinematic equation

        v  =  u -   g * \frac{t}{2}

So v is the velocity at maximum height and the value is  v = 0 m/s

So

       0   =  u -   9.8 * \frac{ 3.7}{2}

=>   u  =  18.13  \  m/s

Here u  is the initial velocity of the dart as it leaves that gun  

Gnerally the horizontal range of the dart is mathematically represented as

         R  =  \frac{u ^2 sin 2\theta }{g}

For maximum horizontal range the value of  \theta  =  45^o        

So

         R_{max}  =  \frac{ 18.13 ^2 sin 2(45) }{9.8}

=>     R_{max}  = 33.54 \  m

6 0
3 years ago
a lion is stalking an antelope that is running at a speed of 7m/s. At the moment the antelope passes the lion, she gives chase a
fiasKO [112]
Antelope: uniform motion => V = d/t => d = Vt = 7m/s * t

Lion: uniformly accelerated motion, with initial velocity = 0 => d = [1/2]a*t^2 = [1/2]*[5m/s^2]*t^2

7*t = 2.5*t^2=> 2.5t^2 - 7t =0 => t(2.5t - 7) = 0

2.5t - 7 = 0 => t = 7/2.5 = 2.8 m/s^2
7 0
3 years ago
a body weights 28N at a height of 3200km from the earth surface.What will be the gravitational force on that body if its lies on
alekssr [168]

Answer:

The object would weight 63 N on the Earth surface

Explanation:

We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

F_G=G\,\frac{M_E\,m}{d^2} \\28\,\,N=G\,\frac{M_E\,m}{9600000^2}

Now, if the body is on the surface of the Earth, its weight (w) would be:

F_G=G\,\frac{M_E\,m}{d^2} \\w=G\,\frac{M_E\,m}{6400000^2}

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

\frac{w}{28} =\frac{9600000^2}{6400000^2} \\\frac{w}{28} =\frac{9}{4} \\\\ \\w=\frac{9\,*\,28}{4}\,\,\,N\\w=63\,\,N \\

4 0
3 years ago
The eyes of many older people have lost the ability to accommodate, and so an older person’s near point may be more than 25 cm f
tensa zangetsu [6.8K]

Answer:

Smaller refractive power

Explanation:

The refractive power of an eye is the extent to which it can converge or diverge the light rays.

Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.

A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.

Thus the near point also increases and the refractive power becomes smaller.

4 0
3 years ago
What type of acceleration does an object moving in a circular path with constant speed experience?
Marysya12 [62]

An object moving in a circular path has centripetal acceleration. <em>(A)</em>

7 0
3 years ago
Read 2 more answers
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