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2 years ago

He graph below shows the velocity f(t) of a runner during a certain time interval:

Physics

2 answers:

Annette [7]2 years ago

5 0

The following that describes the intercepts on the graph is "The initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds." It is because the starting point of the line is at 4 and then the ending point is at 8.

iragen [17]2 years ago

4 0

Answer is "the initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds".

This is a velocity - time graph.

At t = 0 s, the graph has a velocity as 4 m/s. This means, the runner has an initial velocity as 4 m/s.

At t = 4 s, the runner has reached his maximum velocity as 8 m/s and acceleration is 1 m/s².

After t = 4 s, the velocity has decreased with the time means it is a negative acceleration. 

At t = 8 s, the velocity of the runner has reached to zero means runner has stopped after 8 seconds.

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When time is measured in days, the decay constant for a particular radioactive isotope is 0.16. Determine the time required for

san4es73 [151]

Answer:

The time take is $t = 1.3964 \ days$

Explanation:

From the question we are told that

The decay constant is $\lambda = 0.16$

The percentage fall is $c = 0.80$

The equation for radioactive decay is mathematically represented as

$N(t) = N_o * e^{- \lambda t }$

Where is $N(t)$ is the new amount of the new the isotope while $N_o$ is the original

At initial $N_o = 100$ % = 1

At $N(t ) = 80$ % = 0.80

$0.80 = 1 * e^{- 0.16 t }$

=> $-0.223 = -0.16 t$

=> $t = 1.3964 \ days$

5 0

3 years ago

Read 2 more answers

Why does gravity on Earth have a stronger attraction with you than the sun has with you? Plsssssss help I really need this rn

n200080 [17]

Answer:

Although the Earth has a lesser mass than the Sun, it is far closer to you, allowing for a stronger pull.

Explanation:

5 0

2 years ago

The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size aa ba

tester [92]

Answer:

3 volts

Explanation:

Number of turns in primary coil = $N_{p}$ = 100

Number of turns in secondary coil = $N_{s}$ = 200

Voltage across primary coil = $V_{p}$ = 1.5 volts

Voltage across secondary coil = $V_{s}$ = ?

In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.

$\frac{N_{p} }{N_{s} } =\frac{V_{p} }{V_{s} }\\$

Using the given values, we get:

$\frac{100}{200}=\frac{1.5}{V_{s} }\\V_{s}=1.5 \times \frac{200}{100}\\V_{s}=3$

Thus, the voltage measure across secondary coil would be 3 volts

4 0

3 years ago

Help me quick!!! please!!

Rudik [331]

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is $w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J$

At this point we can simply apply the definition of power, that is $P = \frac wt$ , to get the power of the engine is $39.240 W$

4 0

2 years ago

Read 2 more answers

A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slit

JulsSmile [24]

I am assuming you know the relation obtained between slit width, distance of screen from slits, distance of interference pattern obtained on the screen from the center and the wavelength of monochromatic light used in Young's Double Slit experiment.
λ = $\frac{y*d}{D} = \frac{3.55*10^{-3}*1.25*10^{-4} }{2.25} = 1.97*10^{-7} m$
λ ~ 1.97 ×10⁻⁷m

7 0

3 years ago