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makkiz [27]
3 years ago
5

He graph below shows the velocity f(t) of a runner during a certain time interval:

Physics
2 answers:
Annette [7]3 years ago
5 0
<span>The following that describes the intercepts on the graph is "The initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds." It is because the starting point of the line is at 4 and then the ending point is at 8.

</span>
iragen [17]3 years ago
4 0

Answer is "the initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds<span>".

This is a velocity - time graph. 

At t = 0 s, the graph has a velocity as 4 m/s. This means, the runner has an initial velocity as 4 m/s. 

At t = 4 s, the runner has reached his maximum velocity as 8 m/s and acceleration is 1 m/s²</span>.

After t = 4 s<span>, the </span>velocity has decreased<span> <span>with the time means it is a </span></span>negative acceleration<span>. </span>

<span>At </span>t = 8 s<span>, the velocity of the runner has reached to </span>zero means r<span>unner has stopped after 8 seconds.</span>

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A particle in uniform circular motion requires a net force acting in what direction?
mel-nik [20]
The net force will point towards the acceleration of the object, as supported by Newton's second law.
6 0
3 years ago
An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.6 m/s. A child on a bridge, 71 m abo
saveliy_v [14]

Answer:

21.28 m

Explanation:

height, h = 71 m

velocity of raft, v = 5.6 m/s

let the time taken by the stone to reach to raft is t.

use second equation of motion for stone

h = ut + \frac{1}{2}at^{2}

u = 0 m/s, h = 71 m, g = 9.8 m/s^2

71 = 0 + 0.5 x 9.8 x t^2

t = 3.8 s

Horizontal distance traveled by the raft in time t

d = v x t = 5.6 x 3.8 = 21.28 m

3 0
3 years ago
The movement of water is able to transport minerals and nutrients. Which statement best explains why water is able to do this?
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no it can't do this why because I think that it is water and it can not go any where.

3 0
3 years ago
Read 2 more answers
2. How long must a 400 W electrical engine work in order to produce 300 kJ of work?
yanalaym [24]

Answer:

Explanation:

400 W = 400 J/s

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7 0
3 years ago
In an RC circuit, what fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for
4vir4ik [10]

Answer:

The  fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is  

      k  = 0.903

Explanation:

From the question we are told that

     The time  constant  \tau  =  3

The potential across the capacitor can be mathematically represented as

     V  =  V_o  (1 -  e^{- \tau})

Where V_o is the voltage of the capacitor when it is fully charged

    So   at  \tau  =  3

     V  =  V_o  (1 -  e^{- 3})

     V  =  0.950213 V_o

   Generally energy stored in a capacitor is mathematically represented as

             E = \frac{1}{2 } * C  * V ^2

In this equation the energy stored is directly proportional to the the square of the potential across the capacitor

Now  since capacitance is  constant  at  \tau  =  3

        The  energy stored can be evaluated at as

         V^2 =  (0.950213 V_o )^2

       V^2 =  0.903  V_o ^2

Hence the fraction of the energy stored in an initially uncharged capacitor is  

      k  = 0.903

4 0
3 years ago
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