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makkiz [27]
3 years ago
5

He graph below shows the velocity f(t) of a runner during a certain time interval:

Physics
2 answers:
Annette [7]3 years ago
5 0
<span>The following that describes the intercepts on the graph is "The initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds." It is because the starting point of the line is at 4 and then the ending point is at 8.

</span>
iragen [17]3 years ago
4 0

Answer is "the initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds<span>".

This is a velocity - time graph. 

At t = 0 s, the graph has a velocity as 4 m/s. This means, the runner has an initial velocity as 4 m/s. 

At t = 4 s, the runner has reached his maximum velocity as 8 m/s and acceleration is 1 m/s²</span>.

After t = 4 s<span>, the </span>velocity has decreased<span> <span>with the time means it is a </span></span>negative acceleration<span>. </span>

<span>At </span>t = 8 s<span>, the velocity of the runner has reached to </span>zero means r<span>unner has stopped after 8 seconds.</span>

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As sea floor spreading occurs, the oceanic plate _______.
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Becomes older

Explanation:

As sea floor spreading occurs at divergent margins, the oceanic plate becomes older. Younger plate margin are the closest to the margin whereas the older plates bushes backward away from the spreading centers.

  • The idea that the sea floor spreads was postulated by Harry Hess shortly after the second world war around the 1960's.
  • At divergent margins new crust materials from the mantle are brought to the surface.
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Learn more:

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8 0
3 years ago
What will happen to the current if the voltage is reduced to one half? ​
stira [4]
We use v=IR and assuming the resistance doesn’t change we can also say that the voltage and current (I) are directly proportional which means the voltage also decreases by 1/2
8 0
2 years ago
2. A rock is shot straight up into the air with a slingshot that had been stretched 0.30 m. Assume
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4 0
3 years ago
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The relative humidity would be ________% if the actual water vapor in the air was 4 grams per cubic meter, the air's capacity to
AveGali [126]

Answer:

50%

Explanation:

Humidity is the amount water vapor present in the atmosphere.

Relative humidity is defined as the ratio of partial water vapor present in air to the actual water vapor at a particular temperature. It is expressed in percentage and the higher the percentage RH, the more the saturated water vapor present in the atmosphere and vice versa.

It is expressed mathematically as shown;

RH = actual water vapor in air/saturated water vapor × 100%

If the actual water vapor in the air was 4 grams per cubic meter and the air's capacity to hold water vapor was 8 grams per cubic meter

Actual water vapor = 4g/cm³

Air's water capacity (saturated water vapor) = 8g/cm³

RH = 4/8×100

RH = 50%

3 0
3 years ago
The density of a block of wood is 694 kg/m3. Its mass is 689 g. We tie the block to the bottom of a swimming pool using a single
Serhud [2]

Answer:

<em>The tension in the string = 2.065 N</em>

Explanation:

From Archimedes principle,

R.d = density of the wood block/density of water = weight of the wood block/Upthrust of the wood block in water.

R.d = D₁/D₂ = W/U

W/U =D₁/D₂.................................. Equation 1

Where W = weight of the wood block, U = upthrust of the wood block in water, D₁ = Density of the wood block, D₂ = Density of water.

Making U the subject of the equation,

U = WD₂/D₁........................... Equation 2

Given: W =  mg = (689/1000)9.8 = 6.75 N,  D₁ = 694 kg/m³, D₂ = 1000 kg/m³.

Substituting these values into equation 2,

U = 6.75(694)/1000

U = 4684.5/1000

U = 4.685 N.

Note: Three forces act on the wood block in the pool. and they are

(i) The weight(W) acting downs

(ii) The upthrust (U) acting upwards,

(iii) The Tension (T) in the string, acting upwards.

Thus,

W = U+T

T = W - U ................................. Equation 3

Where W = 6.75 N, U = 4.685 N

T = 6.75 - 4.685

T = 2.065 N.

T = 2.065 N

<em>Thus the tension in the string = 2.065 N</em>

7 0
3 years ago
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