Answer:
Net force, F = 44.66 N
Explanation:
It is given by,
Initial velocity of the person, u = 0
Final velocity of the person, v = 0.68 m/s
Distance, s = 0.428 m
Combined mass of the person and the kayak, m = 82.7 kg
We need to find the net force acting on the kayak i.e.
F = ma...........(1)
Firstly, we will calculate the value of "a" from third equation of motion as :
Put the value of a in equation (1) as :
F = 44.66 N
So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.
M=F/A
Which means 30 divided by 5 m/s is 6kg(mass)
Answer:
26.83 N.
Explanation:
If the angle between two vector is 90°, to get the resultant, we use Pythagoras theorem.
a² = b²+c²......................... Equation 1
Where a = R = Resultant, b = 12 N, c = 24 N.
Substitute these values into equation 1
R² = 12²+24²
R² = 144+576
R² = 720
√R² = √720
R = 26.83 N.
Hence, the result of the two force is 26.83 N.
Answer:
The focal length of the appropriate corrective lens is 35.71 cm.
The power of the appropriate corrective lens is 0.028 D.
Explanation:
The expression for the lens formula is as follows;
Here, f is the focal length, u is the object distance and v is the image distance.
It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.
Put v= -71.4 cm and u= 24.0 cm in the above expression.
f= 35.71 cm
Therefore, the focal length of the corrective lens is 35.71 cm.
The expression for the power of the lens is as follows;
Here, p is the power of the lens.
Put f= 35.71 cm.
p=0.028 D
Therefore, the power of the corrective lens is 0.028 D.
Answer:
Explanation:
separation between two gaps, d = 5 cm
angle between central and second order maxima, θ = 0.52°
use
d Sinθ = n λ
n = 2
0.05 x Sin 0.52° = 2 x λ
λ = 2.27 x 10^-4 m
λ = 226.9 micro metre
