Why do electrons move from the negative end of the tube to the positive end

A golf ball is struck at ground level. The speed of the golf ball as a function of the time is shown in Figure 4-36, where t = 0

lana66690 [7]

In your question where as a golf ball is struck at a ground level and the speed of the ball as a function of time is in the figure where time t=0 and va = 16m/s and vb=32m/s. The following is the answer:
a) How far does the golf ball travel horizontally before returning to ground level?
-<span>80m</span>
<span>(b) What is the maximum height above ground level attained by the ball?
</span>-39.87m

3 0

3 years ago

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A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processe

Allushta [10]

To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.

Mathematically this expression can be given as

$P = \sigma Ae\Delta T^4$

Where

A = Surface area of the Object

$\sigma =$ Stefan-Boltzmann constant

e = Emissivity

T = Temperature (Kelvin)

Our values are given as

$A = 1.36m^2$

$\Delta T^4 = T_2^4 -T_1^4 = 307^4-T_1^4$

$\sigma = 5.67*10^{-8} J/(s m^2 K^4)$

$P = 122J/s$

$e = 0.7$

Replacing at our equation and solving to find the temperature 1 we have,

$P = \sigma Ae\Delta T^4$

$P = \sigma Ae (T_2^4 -T_1^4)$

$122 = (5.67*10^{-8})(1.36)(0.7)(307^4-T_1^4)$

$T_1 = 285.272K = 12.122\°C$

Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C

8 0

3 years ago

Calculate the power of a car that does 50,000 J of work in 7s during a race

Fantom [35]

Answer =7,142.9W

I hope this helps (:

6 0

3 years ago

HELP PLS! :/

zlopas [31]

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

7 0

2 years ago

The range of a projectile depends not only on v0 and θ0 but also on the value g of the free-fall acceleration, which varies from

ElenaW [278]

Answer:

0.0106491902979 m

Explanation:

$v_0$ = Velocity of jump

$\theta_0$ = Angle of jump

g = Acceleration due to gravity

Jump at Berlin

$R_1=\dfrac{v_0sin2\theta_0}{g_1}=8.09\ m$

Jump at Melbourne

$R_2=\dfrac{v_0sin2\theta_0}{g_2}$

The difference is

$\Delta R=R_2-R_1\\\Rightarrow \Delta R=\dfrac{v_0sin2\theta_0}{g_2}-\dfrac{v_0sin2\theta_0}{g_1}\\\Rightarrow \Delta R=v_0sin2\theta_0(\dfrac{1}{g_2}-\dfrac{1}{g_1})\\\Rightarrow \Delta R=v_0sin2\theta_0(\dfrac{1}{g_2}-\dfrac{1}{g_1})\\\Rightarrow \Delta R=\dfrac{v_0sin2\theta_0}{g_1}(\dfrac{g1}{g2}-1)\\\Rightarrow \Delta R=R_1(\dfrac{g1}{g2}-1)\\\Rightarrow \Delta R=8.09(\dfrac{9.8128}{9.7999}-1)\\\Rightarrow \Delta R=0.0106491902979\ m$

The record would have differed by 0.0106491902979 m

5 0

3 years ago