In your question where as a golf ball is struck at a ground level and the speed of the ball as a function of time is in the figure where time t=0 and va = 16m/s and vb=32m/s. The following is the answer:
a) How far does the golf ball travel horizontally before returning to ground level?
-<span>80m</span>
<span>(b) What is the maximum height above ground level attained by the ball?
</span>-39.87m
To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.
Mathematically this expression can be given as

Where
A = Surface area of the Object
Stefan-Boltzmann constant
e = Emissivity
T = Temperature (Kelvin)
Our values are given as





Replacing at our equation and solving to find the temperature 1 we have,




Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C
Answer =7,142.9W
I hope this helps (:
Explanation:
formula: Vi = Vf - (at)
Vi: intial velocity
Vf: final velocity
a: acceleration
t: time
fill in formula with the numbers you are given
Vi= 41.6m - ((9.81 m/s^2)(1.89s))
parenthesis first according to pemdas
Vi= 41.6m - 18.54m/s
Answer: 23.06m/s
disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck
Answer:
0.0106491902979 m
Explanation:
= Velocity of jump
= Angle of jump
g = Acceleration due to gravity
Jump at Berlin

Jump at Melbourne

The difference is

The record would have differed by 0.0106491902979 m