Answer: 87500J
Explanation:
Given that,
Power exerted by crane = 3,500 W
Time taken = 25 seconds
work done by crane = ?
Since power is the rate of work done per unit time, then power is workdone by the crane divided by the time taken.
i.e power = work / time
3,500 W = work / 25 seconds
Work = 3500W x 25 seconds
Work = 87500J
Thus, 87500 joules of work was done by the crane.
Answer:
Troposphere
Explanation:
The troposphere is the lowest layer of the Earth's atmosphere. The earth's atmosphere has the following layers:
- Troposphere - Stratosphere - Mesosphere -Thermosphere - Exosphere
The troposphere lies 10 km above the land surface and most weather phenomena and conditions (e. g. clouds, turbulence) occur there.
Most of the water vapor in the atmosphere is in the troposphere (about 99%) and most of the atmosphere's mass is contained in the troposphere (75%)
Answer:
from the cup to the hand
Explanation:
Heat present one body transfer to the other less heat body or cold body through physical contact is called conduction. The temperature of the cup is higher which is 90°C whereas the temperature of the hand is 36°C so difference between temperature of both bodies causes conduction of heat energy from hotter body to cold body so we can conclude that the heat energy will transfer from the cup to the hand.
Answer:
0.68 m
Explanation:
α = dL / L1*(dT)
dL = L1(dT) * α
Initial length, L1 = 100
Chang in Length =dL
α linear expansivity ; dL = change in length ; dT = change in temperature ; L1 = initial length
α of iron rod = 1.13 * 10^-5 k
dL = 100(40 - 10) * 1.13 * 10^-5
dL = 100(30) * 1.13 * 10^-5
dL = 3000 * 1.13 * 10^-5
dL = 3390 * 10^-5
dL = 0.0339 m
Error :
Distance measured = 2km = (2 * 1000) = 2000m
[Distance measured / (initial length + change in length)] × change in length
Error = (2000 / (100 + 0.0339)) * 0.0339
Error = (2000 / 100.0339) * 0.0339
Error = 19.993222 * 0.0339
Error = 0.6777702
Error = 0.68 m
Answer:
symbolic solution for the coefficient of friction between the baby and the sled is
Explanation:
From the question we are told that
The mass of the boy is 
The mass of the shed is 
The mass of the baby is 
The maximum acceleration for the baby to stay is a
Generally the frictional force between the baby and the shed is mathematically represented as
Here N is the normal force acting on the baby which is mathematically represented as
=> 
Now for the baby not the slip off the shed the frictional force between the baby and the shed must be equal to the the force applied by the child
The force applied by the child is mathematically represented as
![F = [M_s+m] * a](https://tex.z-dn.net/?f=F%20%20%3D%20%20%5BM_s%2Bm%5D%20%2A%20a)
So
![\mu * m * g = [M_s+m] * a](https://tex.z-dn.net/?f=%20%5Cmu%20%2A%20%20m%20%2A%20%20g%20%20%3D%20%20%5BM_s%2Bm%5D%20%2A%20a)
=>
