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mrs_skeptik [129]
3 years ago
5

In the following reaction, how many moles of H2O are created when 7 moles of oxygen are consumed?

Chemistry
1 answer:
notka56 [123]3 years ago
4 0

Answer:

C

Explanation:

You can see in the chemical equation that 7 O_{2} are used up to produce 6H_{2}O

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Complete the electron-dot structure of s-allylcysteine, showing all lone-pair electrons.
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Identify the situation where work is being done. Carrying a box of crayons across the room. Lifting a backpack off the floor Hol
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Lifting the backpack off the floor. Force is being applied in only one direction then (up) which is what constitutes as work. Carrying the box of crayons applies force in two directions (up and forward), which cancel each other out. Work has a vector, which is a quantity containing both direction and magnitude (one, finite direction, not two).
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Given that the density of gold and sand are 19. 3 g/cm^3 and 2. 95 g/cm^3, respectively, and that the density of the mixture is
SOVA2 [1]

The percent by mass of gold in the mixture will be 34.5%.

How to calculate the percentage?

The following information can be deduced based on the information given:

Density of gold = 19.3 g/cm³.

Density of sand = 2.94 g/cm³

Density of mixture = 4.17 g/cm³

It should be noted that when we find the volume fo gold on a 1cm³ sample, then we can be able to find that mass. The volume of gold will be calculated thus:

4.17 = [(19.3x + 2.95(1 - x)]

4.17 = 19.3x + 2.95 - 2.95x

4.17 = 16.35x + 2.95

x = 0.0746cm³

The mass of gold will be:

= 0.0746 × 19.3

= 1.44

The percent by mass of gold in the mixture will be:

= 1.44/4.17 × 100

= 34.5%

In conclusion, the percent by mass of gold in the mixture will be 34.5%.

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Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.

The kilogram is the primary mass unit in the SI (kg). Even though weight is frequently measured using a spring scale rather than a balancing scale and directly compared with known masses, mass is not the same as weight in physics. Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. Given that weight is a force.

To learn more about  mass equation visit here:

brainly.com/question/19600926?referrer=searchResults

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3 0
2 years ago
For the following SN1 solvolysis reaction, select the correct rate equation and the overall reaction order (note: CH3OH is the s
sineoko [7]

Answer:

Explanation:

  • rate = K[(CH3)3CCl]
  • overall order is also first order

Since we are told that CH3OH is the solvent for the reaction, as such the rate law equation will only be written for (CH3)3CCl .

8 0
3 years ago
If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.
lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer :  The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process  = 9.00 year

a = initial amount or moles of the reactant  = 1.000 g

a - x = amount or moles left after decay process  = 0.805 g

Putting values in above equation, we get:

k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}

k=0.0241\text{ year}^{-1}

To calculate the half-life, we use the formula :

k=\frac{0.693}{t_{1/2}}

0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=28.8\text{ years}

Therefore, the half-life of strontium-90 is 28.8 years.

5 0
3 years ago
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