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3 years ago

5

The water released by the reaction (mass = 0.00020 g) was calculated as was the

1 answer:

olga55 [171]3 years ago

7 0

I’m not to sure but let me figure it out hold up

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1. Because its structure is more complex,

Mashutka [201]

Answer:

Organs are more complex units than tissues. An organ is an organization of several different kinds of tissues so arranged that together they can perform a special function. For example, the stomach is an organization of muscle, connective, epithelial, and nervous tissues.

Explanation:

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3 0

3 years ago

How should you measure the mass of a given powdered substance??

Lelu [443]

To measure the mass of a given powdered substance do the following:
1. Zero the weighing balance, that is, put the weigh balance at zero mark.
2. Put an empty weighing paper on the balance and take its reading. Record it as X1.
3. Use spatula to put the powder you want to measure on the weighing paper on the balance. Take your reading and record it as X2.
The mass of the powered is X2 - X1.

6 0

3 years ago

Find the number of molecules in .815 mole of O2

Simora [160]

Answer:

4.9 × 10²³ molecules

Explanation:

Given data:

Number of molecules = ?

Number of moles of oxygen = 0.815 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.815 mol × 6.022 × 10²³ molecules / 1 mol

4.9 × 10²³ molecules

6 0

3 years ago

Hoochie [10]

Answer:

Salt and water

Explanation:

The reaction of an acid and a base forming a salt and water.

3 0

2 years ago

Tetrahydrofuran (THF) is a common organic solvent with a boiling point of 339 K. Calculate the total energy (q) required to conv

poizon [28]

Explanation:

For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.

$Q_{1} = mC_{1} \Delta T_{1}$

Putting the given values into the above equation as follows.

$Q_{1} = mC_{1} \Delta T_{1}$

= $27.3 g \times 1.70 J/g K \times 41$

= 1902.81 J

Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.

$Q_{2}$ = energy required = $mL_{v}$

$L_{v}$ = latent heat of vaporization

Therefor, calculate the value of energy required as follows.

$Q_{2}$ = $mL_{v}$

= $27.3 \times 444$

= 12121.2 J

Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.

$Q_{3} = mC_{2} \Delta T_{2}$

Value of $C_{2}$ = 1.06 J/g, $\Delta T_{2}$ = (373 -339) K = 34 K

Hence, putting the given values into the above formula as follows.

$Q_{3} = mC_{2} \Delta T_{2}$

= $27.3 g \times 1.06 J/g \times 34 K$

= 983.892 J

Therefore, net heat required will be calculated as follows.

Q = $Q_{1} + Q_{2} + Q_{3}$

= 1902.81 J + 12121.2 J + 983.892 J

= 15007.902 J

Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.

5 0

3 years ago