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ki77a [65]
3 years ago
6

A hot air balloon is filled to 1250 m3 at 27 C. At what temperature will the balloon be filled to 1600 m3 if the pressure remain

s constant?
Please help!!
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
7 0

Answer:

384.2 K

Explanation:

First we convert 27 °C to K:

  • 27 °C + 273.16 = 300.16 K

With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:

  • T₁V₂=T₂V₁

Where in this case:

  • T₁ = 300.16 K
  • V₂ = 1600 m³
  • T₂ = ?
  • V₁ = 1250 m³

We input the data:

300.16 K * 1600 m³ = T₂ * 1250 m³

And solve for T₂:

T₂ = 384.2 K

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What is the mass of one mole of product? (Remember the law of conservation of mass)
denis23 [38]

Answer:

To calculate the no. of moles you must know mass and molar mass of the product

Explanation:

# of moles = mass/molar mass

4 0
1 year ago
iron combines with oxygen to form rust. given the chemical reaction, how many grams of rust would be produced if 3 grams of reac
tia_tia [17]

Answer:

I believe its 1 gram

Explanation:

8 0
3 years ago
Calculate the change in ph when 3.00 ml of 0.100 m hcl(aq) is added to 100.0 ml of a buffer solution that is 0.100 m in nh3(aq)
nikklg [1K]

The change in pH is calculated by:

pOH = Protein kinase B + log [NH4+]/ [NH3] 

Protein kinase B of ammonia = 4.74 

initial potential of oxygen hydroxide= 4.74 + log 0.100/0.100 = 4.74 
pH = 14 - 4.74=9.26 

moles NH4+ = moles NH3 = 0.100 L x 0.100 M = 0.0100 
moles H+ added = 3.00 x 10^-3 L x 0.100 M=0.000300 

NH3 + H+ = NH4+ 
moles NH3 = 0.0100 - 0.000300=0.00970 
moles NH4+ = 0.0100 + 0.000300=0.0103 

pOH = 4.74 + log 0.0103/ 0.00970= 4.77 
oH = 14 - 4.77 = 9.23 

the change is  = 9.26 - 9.23 =0.03 

7 0
3 years ago
Using henry's law, calculate the molar concentration of o2 in the surface water of a mountain lake saturated with air at 20 ∘c a
s2008m [1.1K]

Answer: The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

Explanation:

Partial pressure of the O_2gas = 685 torr = 0.8905 bar

1 torr = 0.0013 bar

According Henry's law:

p_{o_2}=K_H\times\chi_{O_2}

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar

0.0013=34860 bar\times \chi_{O_2}

\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}

Let the number of moles of O_2 gas in 1 liter water be n.

1 Liter water = 1000 g of water

Moles of water in 1 L n_w=\frac{1000 g}{18 g/mol}=55.55 mol

\chi_{O_2}=\frac{n}{n+n_w}

2.56\times 10^{-5}=\frac{n}{n+55.55}

n=1.43\times 10^{-7} moles

Molarity=\frac{\text{Moles of}O_2}{Volume}

Molar concentration of oxygen gas in 1 L of water:

=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L

The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

4 0
3 years ago
Will mark brainliest
poizon [28]

Explanation:

solid, liquids and gases are all made up of atoms and molecules

contrast

solids have a definite shape, liquids takes the shape of the container that contains it while gases do not have a shape

solids move about their mean positions, liquids move more freely while gases move in random motion

solids cannot be easily compressed, liquids can be compressed while gases can be easily compressed

5 0
3 years ago
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