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ANTONII [103]
3 years ago
7

The electron dot structure for CI is

Chemistry
2 answers:
finlep [7]3 years ago
6 0
The correct option is C.
A Lewis dot diagram is a representation of the valence electron of  an atom, which uses dot around the symbol of the atom. Chlorine has seven electrons in its outermost shell, these seven electrons are arranged in form of dot around the atom of chlorine. If you count the number of dot given in option C, you will notice that they are seven.
Igoryamba3 years ago
5 0

Answer:

C. Cl (w/ 2 dots above and to the left of the C, 1 underneath, and 2 dots to the right of the 1).

Explanation:

Hello,

Electron dot structure is related with the Lewis structure showing the valence electrons for a given element. In this case, the involved element is chlorine, whose symbol is Cl, which is located at the group VIIA, it means that it has seven valence electrons (the number of electrons at its outer shell) around it when expressing the aforesaid structure which is arranged as described on the C. option, this is substantiated via the attached picture showing such arrangement.

Best regards.

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3 years ago
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tia_tia [17]
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3 years ago
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

By the Nersnt equation:

E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

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3 years ago
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