Answer:
If the acceleration is constant, the movements equations are:
a(t) = A.
for the velocity we can integrate over time:
v(t) = A*t + v0
where v0 is a constant of integration (the initial velocity), for the distance traveled between t = 0 units and t = 10 units, we can solve the integral:
Where to obtain the actual distance you can replace the constant acceleration A and the initial velocity v0.
Answer:
The magnitude of the force net is an acting object multiplied by acceleration of the object
First of all, don't forget that the sun is 400 times farther from us than the moon is. That fact alone tells us that anything on the earth is attracted to each kilogram of the moon with a force that's 160,000 times stronger than the force that attracts it to each kilogram of the Sun.
But more to your point ... The tides ARE greatly influenced by the sun. That's why tides are considerably higher at New Moon, when the sun and moon are both pulling in the same direction.
I think that it’s the first one
Answer:
The first interval is walked slowly, this is a straight line with a small slope
Second interval stops, which gives a horizontal line, indicating the same position
Third interval, walk back, straight downhill
Explanation:
In this problem we have a uniform movement, this means that the acceleration in each intervals
x = v t
The first interval is walked slowly, this is a straight line with a small slope
Second interval stops, which gives a horizontal line, indicating the same position
Third interval, walk back, straight downhill
