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3 years ago

Can someone explain why light from distant galaxies is projected. Plz

1 answer:

8 0

I'm not exactly sure what you mean by 'projected'. The light from other galaxies
is the light generated by all the stars in that galaxy. It comes out of a distant star,
spends millions of years traveling straight through space, and millions of years
later, a tiny bit of that same light zooms straight into your eye. Practically nothing
happened to it on the way between the star in the distant galaxy and the back of
your eye. Pretty amazing !

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A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow

shusha [124]

Answer:

150000000

$\dfrac{F_e}{F_g}=0.00000203873598369$

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

$1\ C=6.25\times 10^{18}\ electrons$

Number electrons is

$n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000$

The number of electrons added or removed was 150000000

Force is given by

$F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N$

The ratio is

$\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369$

The ratio is $\dfrac{F_e}{F_g}=0.00000203873598369$

Balancing the forces we get

$Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C$

The electric field required is 49050000 N/C

4 0

3 years ago

A wave with a frequency of 32 Hz has a wavelength of 9 meters. At what speed will this

jarptica [38.1K]

Answer:

228 m/s

Explanation:

f = 32 Hz

λ = 9 m

v = ?

v = f λ

v = (32 Hz) (9 m)

v = 288 m/s

6 0

3 years ago

A force of 100N is applied to an area of 100mm².what is the pressure exerted on the area in N/m².

Dmitry_Shevchenko [17]

Answer:

P = 1000000[Pa] = 1000 [kPa]

Explanation:

To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.

$P=F/A$

where:

P = pressure [Pa] (units of pascals)

F = force = 100 [N]

A = area = 100 [mm²]

But first we must convert the units from square millimeters to square meters.

$A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2} } =0.0001[m^{2} ]$

Now replacing:

$P=100/0.0001\\P=1000000[Pa]$

3 0

2 years ago

Explain why a diverging lens is used to correct nearsightedness (difficulty seeing objects far away).

Darina [25.2K]

Answer:

so that it can diverge the light to make sure that it focused on the ratina and the image is formed.

Explanation:

nearsightedness is when the light is focused in front of the ratina and for an image to be formed in the eye, the light must be focused on the ratina so to correct that we use the diverging lenses so that it will diverge the light and allow the cornea and the lens to converge it so it is focused on the ratina.

8 0

3 years ago

Read 2 more answers

Find the electron and hole concentrations and fermi level in silicon at 300 k for boron

gogolik [260]

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x $10^4 cm^-3$ .

<h3>Calculation and Explanation</h3>

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at $10^{15} cm^{-3}$ (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = $10^{15} cm^{-3}$

np = $\frac{ni^2}{nA}$

np = $\frac{(9.65 x 10^9)^2}{10^15}$

np= 9.3 x $10^4 cm^-3$

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x $10^{19} / 10^{15}$ )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

To know more about ionization energy, visit:

brainly.com/question/16243729

#SPJ4

4 0

1 year ago