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Nookie1986 [14]
3 years ago
5

James took two pea plants, placing one in a dark closet and the other on a sunny window sill. Both are located in air conditione

d rooms. He then measured the growth of the pea plants after a week. In this experiment, the dark closet is a(N)
a.independent variable
b.control
c.dependent variable
d.constant
Chemistry
2 answers:
inessss [21]3 years ago
5 0

Answer : Option A) independent variable.

Explanation : The dark closet (N) was a part of independent variable as it's variable does not depends on any other variable.

Also, growth factor which was the major aim of study was the dependent variable as it was dependent on closet where it was placed.

Constant was the water as the quantity of water was same for both the plants.

Control was the plant that was used for this experiment, as this was the standard that was used for the comparison of the growth.

maw [93]3 years ago
3 0
A.) independent variable.
the control was or would be the plant at the window. the dependent is the growth of each plant. the constant is the amount of water
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What is the product of the reaction of (S)-2-bromobutane with sodium methoxide in acetone?
Serggg [28]

Answer:

2-methoxybutane

Explanation:

This reaction is an example of Nucleophilic substitution reaction. Also, the reaction of (S)-2-bromobutane with sodium methoxide in acetone, is bimolecular nucleophilic substitution (SN2). The reaction equation is given below.

(S)-2-bromobutane + sodium methoxide (in acetone) → 2-methoxybutane

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2 years ago
A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base
yawa3891 [41]

Answer:

11.39

Explanation:

Given that:

pK_{b}=4.82

K_{b}=10^{-4.82}=1.5136\times 10^{-5}

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.805\ g}{82.0343\ g/mol}

Moles= 0.022\ moles

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.022}{0.055}

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

                                  B +   H₂O    ⇄     BH⁺ +        OH⁻

At t=0                        0.4                          -              -

At t =equilibrium     (0.4-x)                        x           x            

The expression for dissociation constant is:

K_{b}=\frac {\left [ BH^{+} \right ]\left [ {OH}^- \right ]}{[B]}

1.5136\times 10^{-5}=\frac {x^2}{0.4-x}

x is very small, so (0.4 - x) ≅ 0.4

Solving for x, we get:

x = 2.4606×10⁻³  M

pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

<u>pH = 14 - pOH = 14 - 2.61 = 11.39</u>

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2 years ago
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2 years ago
What is the mass of the hydrogen atoms in 1 mole of water
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<u>Answer:</u>

2.0158 grams

<u>Explantion:</u>

We are to find the mass of the hydrogen atoms in 1 mole of water.

We know that the formula of water is: H_2O

We can see, from the above mentioned formula, that water has 2 hydrpgen atoms.

From the periodic table, we get to know that Hydrogen has an atomic mass of 1.00794 grams.

As there are 2 atoms of hydrogen in water so 2 \times 1.00794 = 2.0158 grams is the answer

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3 years ago
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