Answer:
A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium we make the substitution of (Ne) for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes (Ne) 3s1.
Reaction of an alkene with H2 to form an alkane is an example of <u>reduction</u> reaction because there is an <u>increase</u> in the number of C-H bonds.
The pressure of the gas in the flask (in atm) when Δh = 5.89 cm is 1.04 atm
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Atmospheric pressure (Pa) = 730.1 torr = 730.1 mmHg
- Change in height (Δh) = 5.89 cm
- Pressure due to Δh (PΔh) = 5.89 cmHg = 5.89 × 10 = 58.9 mmHg
- Pressure of gas (P) =?
<h3>How to determine the pressure of the gas</h3>
The pressure of the gas can be obtained as illustrated below:
P = Pa + PΔh
P = 730.1 + 58.9
P = 789 mmHg
Divide by 760 to express in atm
P = 789 / 760
P = 1.04 atm
Thus, the pressure of the gas when Δh = 5.89 cm is 1.04 atm
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Missing part of question:
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If 2.34 moles of Mg react with 3.56 moles of l2 and 1.76 moles of Mgl2 form, what is the percent yield?
Answer: 0.9375 g
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of
solution = 0.75 M
Volume of
solution = 25.0 mL = 0.025 L
Putting values in equation 1, we get:
According to stoichiometry :
2 moles of
require = 1 mole of
Thus 0.01875 moles of
will require=
of
Mass of
Thus 0.9375 g of
is required to react with 25.0 ml of 0.75 M HCl