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allsm [11]
3 years ago
7

The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air

Chemistry
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

ΔT= 836.88 °C

ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

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A gas at STP occupies 16 L of space. If the pressure changes to 2.6 atm and the temperature increases to 195 degrees C, what is
Tju [1.3M]

The new volume of a gas at STP that occupies 16L of space is 27.43L.

<h3>HOW TO CALCULATE VOLUME?</h3>

The volume of a given gas can be calculated using the following expression:

P1V1/T1 = P2V2/T2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

1 × 16/273 = 2.6 × V2/468

16/273 = 2.6V2/468

0.0586 × 468 = 2.6V2

V2 = 27.43

Therefore, the new volume of a gas at STP that occupies 16L of space is 27.43L.

Learn more about volume at: brainly.com/question/1578538

5 0
3 years ago
The energy level necessary to enable a reaction to a cure is called the activation true or false
matrenka [14]
The correct answer is true. It was introduced by Svante Arrhenius that activation energy is minimum amount of energy needed to be supplied or released for a chemical reaction to proceed. It is the energy needed to overcome for a reaction to occur.
3 0
4 years ago
The hydroboration of an alkene occurs in ___________ which places the boron of the borane on the ___________ carbon of the doubl
Nana76 [90]

Answer: The hydroboration of an alkene occurs in TWO CONCERTED STEP which places the boron of the borane on the LESS SUBSTITUTED carbon of the double bond. The oxidizing agent then acts as a nucleophile, attacking the electrophilic BORON and resulting in the placement of a hydroxyl group on the attached carbon. Thus, the major product of the hydroboration oxidation reaction DOES NOT follow Markovnikov's rule.

Explanation:

Hydroboration is defined as the process which allows boron to attain the octet structure. This involves a two steps pathway which leads to the production of alcohol.

--> The first step: this involves the initiation of the addittion of borane to the alkene and this proceeds as a concerted reaction because bond breaking and bond formation occurs at the same time.

--> The second step: this involves the addition of boron which DOES NOT follow Markovnikov's rule( that is, Anti Markovnikov addition of Boron). This is so because the boron adds to the less substituted carbon of the alkene, which then places the hydrogen on the more substituted carbon.

Note: The Markovnikov rule in organic chemistry states that in alkene addition reactions, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms bonded to it, while the electron-deficient component adds to the carbon atom with more hydrogen atoms bonded to it.

8 0
3 years ago
A sample of helium, at 20 °c, occupies a volume of 3.17 l at a pressure of 6.21 atm. what volume does this helium sample occupy
Lynna [10]
Boyle's law gives the relationship between pressure of a gas and volume.
It states that at a constant temperature the pressure of gas is inversely proportional to volume of gas.
PV = k
where P - pressure, V - volume and k - constant
P1V1 = P2V2
where parameters for the first instance are given on the left side and parameters for the second instance are given on the right side of the equation.
substituting these values in the equation
6.21 atm x 3.17 L = 5.57 atm x V
V = 3.53 L
new volume is 3.53 L
8 0
4 years ago
How many neutrons does the following nuclide have? 253/100 Fm A. 253 B. 100 C. 153 D. none of these
lara [203]
I believe the correct answer is C. The number of neutrons in the <span>253/100 Fm would be 153. The numbers beside Fm are used to determine this. Two hundred fifty three represents the mass number which is the sum of protons and neutrons in the nuclide while 100 represents the atomic number which is the number of protons. Therefore,

253 = neutrons + 100
neutrons = 153</span>
3 0
3 years ago
Read 2 more answers
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