Well formation of metallic bond depends on free electrons.smaal sized atoms hold their electrons more firmly as compared to large size atoms ,this z due to distance of outer shell electrons by nucleus..in this way no of free electrons affect strength of metallic bond..smaal sized atoms release less free electrons..
Answer:
measuring the zero intensity point, we can deduce the movement of the screen.
The distance from the center of the pattern to the first zero is proportional to the distance to the screen,
Explanation:
The expression for the diffraction phenomenon is
a sin θ = m λ
for the case of destructive interference. In general the detection screen is quite far from the grid, let's use trigonometry to find the angles
tan θ = y / L
in these experiments the angles are small
tan θ = sin θ / cos θ = sin θ
sunt θ = y / L
we substitute
a
= m λ
y = m L λ / a
therefore, by carefully measuring the zero intensity point, we can deduce the movement of the screen.
The distance from the center of the pattern to the first zero is proportional to the distance to the screen, so you can know where the displacement occurs, it should be clarified that these displacements are very small so the measurement system must be capable To measure quantities on the order of hundredths of a millimeter, a micrometer screw could be used.
Answer:
<em>The lighten travels 0.853 miles.</em>
Explanation:
Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.
v = 2x/t .......................................... Equation 1
making x the subject of the equation
x = vt/2........................................ Equation 2
Where v = velocity of sound in air, x = distance traveled by the sound, t = time
Given: v = 344 m/s t = 8 s
Substituting into equation 2
x = 344(8)/2
x = 1376 m.
x = 1376×0.00062 miles = 0.853 miles
<em>Thus the lighten travels 0.853 miles.</em>
The speed and distances are directly proportional. Use ratios to solve for vertical y-distance. The ratio of x-distance west to y-distance north equals the x-velocity to y-velocity.
x/y = vx/vy
41/y = 8.6/5.2
41/y = 1.65
41/1.65 = y
24.8 m = y
100 ml
100 ml of the stock solution is required to prepare the order.
We know that C1V1 = C2V2
where C1= 2%
V1 = 500ml
C2= 10%
V2 = ?
V2 = C1V1 / C2
= 500 * 2% / 10%
=100
V2 = 100 ml
<h3>What is meant by stock solution?</h3>
- A stock solution is a sizable amount of a typical reagent in a standardized concentration, like sodium hydroxide or hydrochloric acid.
- This phrase is frequently used in analytical chemistry while doing operations like titrations where it's crucial to employ precise solution concentrations.
<h3>What distinguishes a standard solution from a stock solution?</h3>
- The main distinction between stock solution and standard solution is that the former is a highly concentrated solution while the later is a solution whose concentration is precisely known.
- Because standard solutions frequently arrive as stock solutions, the phrases "stock solution" and "standard solution" are connected.
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