Outline the process used to test the following hypothesis: Titanium cages are stronger than steel cages for hockey goalie masks.

to determine cam ring speed you must use a ___________________,____________________or a________________

saul85 [17]

Answer:

=> The total numbers of cylinders on the engine.

=> Total number of lobes in the cam ring.

=> The direction at which the cam ring rotates.

Explanation:

A cam is a kind of ring and a device that is being used in engines. One or the main purpose of using cams in engines us because it helps in the change or transformation of the rotational movement of the engine to a translational one. Instead of using a cam ring, a cam roller can be used in place.

There are three things that can be used to to determine the speed of cam ring speed and they are given below as;

=> The total numbers of cylinders on the engine.

=> The Total number of lobes in the cam ring.

=> The direction at which the cam ring rotates.

5 0

4 years ago

Look at the data set below.

Goshia [24]

The answer would be 7

3 0

4 years ago

Read 2 more answers

For what type of metal is high speed steel drill best suited?

Harrizon [31]

ANSWER-
I believe it would be high speed steel

8 0

3 years ago

Read 2 more answers

Three methods by which the value of the unknown resistance can be determined

Contact [7]

Answer:

The Meter bridge is the modification of Wheatstone's network used to determine the value of unknown resistance. The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.

5 0

3 years ago

Two balanced Y-connected loads in parallel, one drawing 15kW at 0.6 power factor lagging and the other drawing 10kVA at 0.8 powe

NemiM [27]

Answer:

(a) attached below

(b) $pf_{C}=0.85$ $lagging$

(c) $I_{C} =32.37 A$

(d) $X_{C} =49.37$ Ω

(e) $I_{cap} =9.72 A$ and $I_{line} =27.66 A$

Explanation:

Given data:

$P_{1}=15 kW$

$S_{2} =10 kVA$

$pf_{1} =0.6$ $lagging$

$pf_{2}=0.8$ $leading$

$V=480$ $Volts$

(a) Draw the power triangle for each load and for the combined load.

$\alpha_{1}=cos^{-1} (0.6)=53.13$ °

$\alpha_{2}=cos^{-1} (0.8)=36.86$ °

$S_{1}=P_{1} /pf_{1} =15/0.6=25 kVA$

$Q_{1}=P_{1} tan(\alpha_{1} )=15*tan(53.13)=19.99$ ≅ $20kVAR$

$P_{2} =S_{2}*pf_{2} =10*0.8=8 kW$

$Q_{2} =P_{2} tan(\alpha_{2} )=8*tan(-36.86)=-5.99$ ≅ $-6 kVAR$

The negative sign means that the load 2 is providing reactive power rather than consuming

Then the combined load will be

$P_{c} =P_{1} +P_{2} =15+8=23 kW$

$Q_{c} =Q_{1} +Q_{2} =20-6=14 kVAR$

(b) Determine the power factor of the combined load and state whether lagging or leading.

$S_{c} =P_{c} +jQ_{c} =23+14j$

or in the polar form

$S_{c} =26.92$ °

$pf_{C}=cos(31.32) =0.85$ $lagging$

The relationship between Apparent power S and Current I is

$S=VI^{*}$

Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.

(c) Determine the magnitude of the line current from the source.

Current of the combined load can be found by

$I_{C} =S_{C}/\sqrt{3}*V$

$I_{C} =26.92*10^3/\sqrt{3}*480=32.37 A$

(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω

$Q_{C} =3*V^2/X_{C}$