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3 years ago

Which of the following are three criteria for creating measurable product attributes?

Engineering

2 answers:

Vinil7 [7]3 years ago

8 0

Answer:

it A

Explanation:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

D. attributes must be complete, practical, and commonly used.

Explanation:

Be complete for every customer need. All measurements must be identified.

Describe an output of the product. The measurement must be dependent on the design of the product.

Be practical so that they can be easily seen and measured.

Include criteria that are commonly used in the marketplace.

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Blank is common during exercise.

dsp73

Answer:

Sweat

Explanation:

As you exercise you respire and warm up due to energy. In turn, two things happen, blood vessels vasodilate (irrelevant to you) and sweat glands sweat more. this sweat then evaporates and cools down the body.

7 0

2 years ago

A spherical balloon with a diameter of 9 m is filled with helium at 20°C and 200 kPa. Determine the mole number and the mass of

SIZIF [17.4K]

Answer:

number of mole is 31342.36 moles

mass is 125.369 kg

Explanation:

Diameter of the spherical balloon d = 9 m

radius r = d/2 = 9/2 = 4.5 m

The volume pf the sphere balloon ca be calculated from

V = $\frac{4}{3} \pi r^3$

V = $\frac{4}{3}* 3.142* 4.5^3$ = 381.75 m^3

Temperature of the gas T = 20 °C = 20 + 273 = 293 K

Pressure of the helium gas = 200 kPa = 200 x 10^3 Pa

number of moles n = ?

Using

PV = nRT

where

P is the pressure of the gas

V is the volume of the gas

n is the mole number of the gas

R is the gas constant = 8.314 m^3⋅Pa⋅K^−1⋅mol^−1

T is the temperature of the gas (must be converted to kelvin K)

substituting values, we have

200 x 10^3 x 381.75 = n x 8.314 x 293

number of moles n = 76350000/2436 = 31342.36 moles

We recall that n = m/MM

or m = n x MM

where

n is the number of moles

m is the mass of the gas

MM is the molar mass of the gas

For helium, the molar mass = 4 g/mol

substituting values, we have

m = 31342.36 x 4

m = 125369.44 g

m = 125.369 kg

3 0

3 years ago

If the atomic radius of copper is 0.128 nm, calculate the volume of its unit cell in cubic meters.

Alex_Xolod [135]

Answer:

Volume of face centered cubic cell= $4.74531*10^{-29} m^3$

Explanation:

Consider the face centered cubic cell:

1 atom at each corner of cube.

1 atom at center of each face.

Consider the one face (ABCD) as shown in attachment for calculation:

Length of the all sides of face centered cubic cell is L.

Volume of face centered cubic cell= L^3

Now Consider the figure shown in attachment:

According to Pythagoras theorem on ΔADC.

$L^{2}+L^2=(4a)^2$ (a is the atomic radius)

$L=\frac{4a}{\sqrt{2}}$ (Put in the formula of Volume)

Volume of face centered cubic cell= L^3

Volume of face centered cubic cell= $(\frac{4a}{\sqrt{2}})^3$

Volume of face centered cubic cell= $(\frac{4(0.128*10^{-9}}{\sqrt{2}})^3$

Volume of face centered cubic cell= $4.74531*10^{-29} m^3$

3 0

4 years ago

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500

lukranit [14]

Answer:

The resulting strain is $1.39\times 10^{-3}$ .

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

$\epsilon=\dfrac{F}{AE}$

E is elastic modulus of Cu is are of cross section

$\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}$

So, the resulting strain is $1.39\times 10^{-3}$ .

6 0

4 years ago

g Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in bin

Phoenix [80]

Answer:

The solution is written in Python

binary = ""
decimal = 13
quotient = int(decimal / 2)
remainder = decimal % 2
binary = str(remainder) + binary
while(quotient >0):
decimal = int(decimal / 2)
quotient = int(decimal / 2)
remainder = decimal % 2
binary = str(remainder) + binary
print(binary)

Explanation:

Firstly, we declare a variable binary and initialize it with an empty string (Line 1). This binary is to hold the binary string.

Next, we declare variable decimal, quotient and remainder (Line 2-4). We assign a test value 13 to decimal variable and then get the first quotient by dividing decimal with 2 (Line 3). Then we get the remainder by using modulus operator, % (Line 4). The first remainder will be the first digit joined with the binary string (Line 5).

We need to repeat the process from Line 3-5 to get the following binary digits. Therefore create a while loop (Line 7) and set a condition that if quotient is bigger than 0 we keep dividing decimal by 2 and calculate the quotient and remainder and use the remainder as a binary digit and join it with binary string from the front (Line 9-11).

At last, we print the binary to terminal (Line 13).

4 0

4 years ago