Two technicians are discussing cylinder honing technician a says a good cross hatch helps to trap the oil and retain it in the c
1 answer:
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Question: The program was not attached to your question. Find attached of the program and the answer.
Answer:
See the explanation for the answer.
Explanation:
#include <iostream>
using namespace std;
int main()
{
cout << "How many students will you enter? ";
int n;
cin>>n;
string *name = new string[n];
double *gpa = new double[n];
for(int i=0;i<n;i++){
cout<<"Enter student"<<(i+1)<<"'s name: ";
cin>>name[i];
cout<<"Enter student"<<(i+1)<<"'s gpa: ";
cin>>gpa[i];
}
cout<<"The list students"<<endl;
cout<<"Name GPA"<<endl;
cout<<"----------------------"<<endl;
for(int i=0;i<n;i++){
cout<<name[i]<<" "<<gpa[i]<<endl;
}
return 0;
}
OUTPUT : See the attached file.
Answer:
X_cp = c/2
Explanation:
We are given;
Chord = c
Angle of attack = α
p u (s) = c 1
p1(s)=c2,
and c2 > c1
First of all, we need to find the resultant normal force on the plate and the total moment about leading edge.
I've attached the solution
Answer:
The required force is 475.009 KN
Explanation:
Given the data in the question;
compression strength of the concrete = 42 MPa
diameter of cylinder = 120mm
First we calculate the Area of the cylinder \;
Area of the cylinder A = × D²
we substitute
First we calculate the Area of the cylinder \;
Area of the cylinder A = × (120)²
Area of the cylinder A = × 14400
Area of the cylinder A = 11309.73355 mm²
Now, we know that;
Stress = P / A
P = Stress × A
we substitute
P = 42 × 11309.73355
P = 475008.809 N
P = ( 475008.809 × )KN
P = 475.009 KN
Therefore, The required force is 475.009 KN