Answer:
Solution given:
1 mole of KCl
22.4l
1 mole of KCl74.55g
we have
0.14 mole of KCl74.55*0.14=10.347g
74.55g of KCl22.4l
10.347 g of KCl22.4/74.55*10.347=3.11litre
volume of each solution contains 0.14 mol of KCl contain 3.11litre.
Answer:
To prevent the mixture from separating substances called emulsifiers can be added. These help to form and stabilise the emulsions, preventing or slowing the water and fat/oil from separating. ... The hydrophilic end of the emulsifier molecule is attracted to the water and the hydrophobic end is attracted to the fat/oil.
Answer:
<h2>2000 N</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 500 × 4
We have the final answer as
<h3>2000 N</h3>
Hope this helps you
Answer:
ITS THE LAST ONE AND THE SECOND ONE
Explanation:
<span>The root mean square velocity of gas molecules as a function of temperature is (M is molecular weight):
v²rms = 3RT/M,
and kinetic energy is given by:
KE = ½Mv ²
We can make the substitution:
KE = ½M3RT/M, or
KE = (3/2)RT.
Notice the molecular weight variable is gone; that means the answer will be the same for F2, Cl2, and Br2:
KE = (3/2) (8.314 J/K*mole) (290 K) = 3617 J/mole.</span>
