The force exerted on the parked car by the moving car is –30000 N
To solve this question, we'll begin by calculating the deceleration of the moving car. This can be obtained as follow:
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.5 s
<h3>Deceleration (a) =?</h3>

<h3>a = - 20 m/s</h3>
Finally, we shall determine the force exerted by the moving car on the parked car. This can be obtained as follow:
Mass of moving car (m) = 1500 Kg
Acceleration (a) = - 20 m/s
<h3>Force (F) =.?</h3>
F = ma
F = 1500 × (-20)
<h3>F = -30000 N</h3>
NOTE: The negative sign indicate force is in opposite direction to the parked car.
Therefore, the force exerted on the parked car by the moving car is –30000 N
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