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Vera_Pavlovna [14]
3 years ago
11

Which of the following is equal to 3.0 liters

Chemistry
1 answer:
motikmotik3 years ago
8 0
Umm where are the choises

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An adult mosquitoes lifespan is about 16 days how many minutes is that
AVprozaik [17]
The answer is 23, 040 minutes. To solve this you can start by changing days in to hours. We know that there are 24 hours in a day. To find how many hours are in 16 days you multiply 24 by 16 which is 384. Next you must find out how many minutes are in 384 hours. we know there are 60 minutes per hour. To find how many minutes are in 384 hours, you multiply 384 by 60. To this you get 23, 040 which is your answer.
3 0
3 years ago
When 1.00 g of boron is burned in o2(g) to form b2o3(s), enough heat is generated to raise the temperature of 733 g of water fro
Bas_tet [7]
<span>Answer: For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees. 4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ. Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work. To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3. .0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>
7 0
3 years ago
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

\%  M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\%  =\frac{m_M}{m_M+32.00}*100 \%

Thus, we solve for the molar mass of the metal to obtain:

59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol

For the subsequent problems, we proceed as follows:

a.

4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

b.

0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH

c.

0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH

Regards!

7 0
3 years ago
A student is asked to convert measurements from grams to kilograms and from kilograms to grams. His answers are shown in bold in
german
It has to be 2 hope this helps

8 0
3 years ago
Read 2 more answers
A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o
Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where \frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}

We're only talking about molar mass and time (t) here so we'll just concentrate on \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}. Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2

{\frac{M2}{131} } = (0.47)^2

{\frac{M2}{131} } = 0.22

M2= 0.22 x 131

M2= 28.93 g/mol

8 0
2 years ago
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