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Elenna [48]
3 years ago
14

Write a balanced equation for the double-replacement precipitation reaction described, using the smallest possible integer coeff

icients. A precipitate forms when aqueous solutions of ammonium bromide and silver(I) nitrate are combined. (Use the lowest possible coefficients. Omit states of matter.)
Chemistry
1 answer:
ahrayia [7]3 years ago
6 0

Answer:

NH4Br + AgNO3 —> AgBr + NH4NO3

Explanation:

When ammonium bromide and silver(I) nitrate react, the following are obtained as shown below:

NH4Br(aq) + AgNO3(aq) —>

In solution, NH4Br(aq) and AgNO3(aq) will dissociate as follow:

NH4Br(aq) —> NH4+(aq) + Br-(aq)

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

The double displacement reaction will occur as follow:

NH4+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq) —> Ag+(aq) + Br-(aq) + NH4+(aq) + NO3-(aq)

NH4Br(aq) + AgNO3(aq) —> AgBr(s) + NH4NO3(aq)

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MgCl₂ ---> Mg(2+) + 2Cl(-)
0,01-x.............x.............2x

MgCl₂ ---> Mg(2+) + 2Cl(-)
0,01-x.............x.............2x
0...................0,01.......0,02

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8 0
3 years ago
What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the
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Answer: The capillary rise(h) in the glass tube is = 0.009m

Explanation:

Using the equation

h = 2Tcosθ/rpg

Given

Contact angle, θ = Zero

h = height of the glass tube=?

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r = radius of the tube = 0.1mm =0.0001m

p= density of ethanol = 0.71g/cm^3

g= 9.8m/s^2

h = (2 * 0.032 * cos 0)/( 710*9.8*0.0001)

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3 years ago
The ideal of stationary orbit was first given by?​
marusya05 [52]

Answer:

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2 years ago
S + 6 HNO3 →→ H₂SO4 +6 NO₂ + 2 H₂O
bija089 [108]
Start with the 19.7 mol HNO3. use dimensional analysis to correctly convert from mol HNO3 to gram H2O. so, it should look similar to 19.7 mol HNO3 x (2 mol H2O/6 mol HNO3) x (18 g H2O/1 mol H2O)

the first parenthesis’ numbers were received from the balanced equation (for every 6 mol HNO3, 2 mol H2O formed). the second is converting from moles to grams by using the molar mass of H2O (1+1+16). you should get 709.2/6. once you divide those, the answer should be 118.2 g H2O. I’m not sure if your computer requires you to use the exact answer or stop at the correct number of significant digits, but if it does then it might just be 118. g H2O.
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Which is an example of a condition in which homeostasis is maintained using a negative feedback loop?
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