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Yuki888 [10]
2 years ago
12

What is the speed of an electromagnetic wave with a frequency of 1.33x10^17Hz and a wavelength of 2.25nm?

Chemistry
2 answers:
pshichka [43]2 years ago
5 0

Wavelength = 2.25nm = 2.25 x 10^(-9)m  

Frequency = 1.33 x 10^17Hz  

Speed = 2.25 x 10^(-9) x 1.33 x 10^17 = 2.99 x 10^8m/s

So the answer is: 2.99 x 10^8m/s

mr Goodwill [35]2 years ago
5 0

Answer : The speed of electromagnetic wave is 2.99\times 10^{8}m/s

Explanation : Given,

Frequency of wave = 1.33\times 10^{17}Hz=1.33\times 10^{17}s^{-1}

Wavelength of wave = 2.25nm=2.25\times 10^{-9}m

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of light

\lambda = wavelength of light

c = speed of electromagnetic wave = ?

Now put all the given values in the above formula, we get:

1.33\times 10^{17}s^{-1}=\frac{c}{2.25\times 10^{-9}m}

c=(1.33\times 10^{17}s^{-1})\times (2.25\times 10^{-9}m)

c=2.99\times 10^{8}m/s

Therefore, the speed of electromagnetic wave is 2.99\times 10^{8}m/s

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muminat

Answer:

The solution will turn red.  

Explanation:

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At about pH 3.4,  the two the forms are present in equal amounts, and the indicator colour is orange.

If you add more acid, you are disturbing the equilibrium.

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3 years ago
What was one important discovery that the Curies made?
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6 0
3 years ago
How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10
Makovka662 [10]

Answer:

It takes  1.9 \times 10^{6} years to distribute all the grains.

Explanation:

In one second, 10^{10} grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 \times 10^{23}

Number of grains distributed in 1 day = 86400 \times 10^{10}

                                                             = 8.64 \times 10^{14}

Number of grains distributed in 1 year= 8.64 \times 10^{14} \times 365

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Time taken = \frac{Number of grains to be distributed}{grains distributed in 1 year}

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7 0
3 years ago
An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average
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Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = \frac{Displacement }{Change in time} = Δx / Δt = \frac{x2 - x1}{t2 - t1}

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

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This is the time taken before the airplane encounters a wind.

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Hence, Average velocity = \frac{1300 - 2100}{1.625 - 2.1}

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