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Yuki888 [10]
3 years ago
12

What is the speed of an electromagnetic wave with a frequency of 1.33x10^17Hz and a wavelength of 2.25nm?

Chemistry
2 answers:
pshichka [43]3 years ago
5 0

Wavelength = 2.25nm = 2.25 x 10^(-9)m  

Frequency = 1.33 x 10^17Hz  

Speed = 2.25 x 10^(-9) x 1.33 x 10^17 = 2.99 x 10^8m/s

So the answer is: 2.99 x 10^8m/s

mr Goodwill [35]3 years ago
5 0

Answer : The speed of electromagnetic wave is 2.99\times 10^{8}m/s

Explanation : Given,

Frequency of wave = 1.33\times 10^{17}Hz=1.33\times 10^{17}s^{-1}

Wavelength of wave = 2.25nm=2.25\times 10^{-9}m

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of light

\lambda = wavelength of light

c = speed of electromagnetic wave = ?

Now put all the given values in the above formula, we get:

1.33\times 10^{17}s^{-1}=\frac{c}{2.25\times 10^{-9}m}

c=(1.33\times 10^{17}s^{-1})\times (2.25\times 10^{-9}m)

c=2.99\times 10^{8}m/s

Therefore, the speed of electromagnetic wave is 2.99\times 10^{8}m/s

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Answer:

a) Ba(OH)₂.8H₂O(s) + <em>2 </em>NH₄SCN(s) → Ba(SCN)₂(s) +<em>10</em> H₂O(l) + <em>2</em> NH₃(g)

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Explanation:

a) For the reaction:

Ba(OH)₂.8H₂O(s) + NH₄SCN(s) → Ba(SCN)₂(s) + H₂O(l) + NH₃(g)

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Ba(OH)₂.8H₂O(s) + NH₄SCN(s) → Ba(SCN)₂(s) +<em>10</em> H₂O(l) + NH₃(g)

To balance hydrogens, the other coefficients are:

Ba(OH)₂.8H₂O(s) + <em>2 </em>NH₄SCN(s) → Ba(SCN)₂(s) +<em>10</em> H₂O(l) + <em>2</em> NH₃(g)

b) As you see in the balanced reaction, 1 mole of barium hydroxide octahydrate reacts with 2 moles of NH₄SCN. 6.5g of Ba(OH)₂.8H₂O are:

6.5 g × (1mol / 315.48g) =<em> 0.0206moles of  Ba(OH)₂.8H₂O</em>. Thus, moles of NH₄SCN that must be used for a complete reaction are:

0.0206moles of  Ba(OH)₂.8H₂O × ( 2 mol NH₄SCN / 1 mol Ba(OH)₂.8H₂O) = <em>0.0412moles of NH₄SCN</em>. In grams:

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